Answer:
Δr=20.45 %
Explanation:
Given that
Rake angle α = 15°
coefficient of friction ,μ = 0.15
The friction angle β
tanβ = μ
tanβ = 0.15
β=8.83°
2φ + β - α = 90°
φ=Shear angle
2φ + 8.833° - 15° = 90°
φ = 48.08°
Chip thickness r given as
r=0.88
New coefficient of friction ,μ' = 0.3
tanβ' = μ'
tanβ' = 0.3
β'=16.69°
2φ' + β' - α = 90°
φ'=Shear angle
2φ' + 16.69° - 25° = 90°
φ' = 49.15°
Chip thickness r' given as
r'=0.70
Percentage change
Δr=20.45 %
Answer:
Relative humidity 48%.
Dew point 74°F
humidity ratio 118 g of moisture/pound of dry air
enthalpy 41,8 BTU per pound of dry air
Explanation:
You can get this information from a Psychrometric chart for water, like the one attached.
You enter the chart with dry-bulb and wet-bulb temperatures (red point in the attachment) and following the relative humidity curves you get approximately 48%.
To get the dew point you need to follow the horizontal lines to the left scale (marked with blue): 74°F
for the humidity ratio you need to follow the horizontal lines but to the rigth scale (marked with green): 118 g of moisture/pound of dry air
For enthalpy follow the diagonal lines to the far left scale (marked with yellow): 41,8 BTU per pound of dry air
