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egoroff_w [7]
2 years ago
10

An animal shelter houses only cats and dogs, and there are 25% more cats than dogs. If there are 40 cats, how many dogs are ther

e, and how many animals are there total?
Mathematics
2 answers:
Inessa [10]2 years ago
5 0
X is  the number of dog
y is the number of cats , y=40
25% of x is  25*x /100=25x/100=x/4
<span>and there are 25% more cats than dogs means y+ x/4=x implies 40=(3/4)x
</span>x=160/3=53
so the number of dogs is 53 and the number of cats is 40
the total number is 53+40=93




Contact [7]2 years ago
4 0
X - number of dogs,
100%+ 25%= 125%
x * 1.25 = 40
x = 40 : 1.25
x = 32
There are 32 dogs.
In total: 32 + 40 = 72 animals.
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CASE3: Odd degree and positive leading coefficient

x\rightarrow -\infty          f(x)\rightarrow -\infty

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CASE4: Odd degree and negative leading coefficient

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Here in the given case we have odd degree and negative leading coefficient

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3 0
2 years ago
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or in decimal form it is approximately  .4737 radians



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