9514 1404 393
Answer:
- -√5
- 3/5
- -4/5
Step-by-step explanation:
The relevant relations are ...
sec = ±√(tan² +1)
cos = 1/sec
csc = 1/sin = ±1/√(1 -cos²)
Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.
__
1. sec(θ) = -√((-2)² +1) = -√5
2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5
3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5
Answer:
6,300kg=6,300,000grams
multiply 6,300 and 1,000 to get 6,300,000
Well, it is a good and interesting question
Such areas could be calculated in a single shoot and also by dividing the whole shape into other shapes and the total area would be the sum of these areas
I prefer the way of a single shoot ...
The figure represents a trapezoid:
its lower base = 21 units
its upper base = 12 units
the normal height between them = 8 units
NOW
The area of a trapezoid = [(sum of bases' lengths) ÷ 2] * height
= [(12 + 21) ÷ 2] * 8 = 132 sq units
Hope that helps
Answer:
B.
Step-by-step explanation:
A. Y=x+2
I thinks that’s right hope this helps :)
