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bulgar [2K]
2 years ago
7

How many ions of aluminum oxide (Al²O³) are there in 200 g of Al²O³??​

Chemistry
1 answer:
valentinak56 [21]2 years ago
6 0

= 6.022 × 1020

Explanation<em>;</em>

Mole of aluminium oxide (Al2O3) is

⇒ 2 x 27 + 3 x 16

Mole of aluminium oxide = 102 g

i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3

Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / (102 x 0.051 molecules)

= 3.011 x 1020 molecules of Al2O3

The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.

Therefore, the number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3)

= 2 × 3.011 × 1020

=<em> 6.022 × 1020</em>

<em>hope </em><em>it </em><em>helps</em><em>_</em>

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