Question

Two semicircles are attached to the sides of a rectangle as shown.

Answer 1

Ok so this answer is 194 try an do it you will get this answer

Answer 2

Answer:

$194\ ft^{2}$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of the rectangle plus the area of one circle (Remember that the area of two semicircles is equal to the area of one circle)

step 1

Find the area of rectangle

The area of rectangle is equal to

$A=bh$

we have

$b=8\ ft$

$h=18\ ft$

substitute

$A=8*18=144\ ft^{2}$

step 2

Find the area of one circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=8/2=4\ ft$

$\pi=3.14$

substitute

$A=(3.14)(4^{2})=50.24\ ft^{2}$

step 3

Find the area of the figure

$144\ ft^{2}+50.24\ ft^{2}=194.24\ ft^{2}$

Round to the nearest whole number

$194.24\ ft^{2}=194\ ft^{2}$