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Mnenie [13.5K]
3 years ago
12

One container is filled with argon gas and the other with krypton gas. If both gases have the same temperature, in which contain

er are the atoms moving faster?
Chemistry
1 answer:
alina1380 [7]3 years ago
7 0

Answer:

Argon

Explanation:

The average kinetic energy of the particles in a gas is given by

KE=\frac{1}{2}mv^2

where

m is the mass of the particles

v is their rms speed

The average kinetic energy of the particles in a gas can also be written as

KE=\frac{3}{2}kT

where

k is the Boltzmann's constant

T is the absolute temperature of the gas

Combining the two equations,

\frac{1}{2}mv^2=\frac{3}{2}kT

We can re-write the equation as

v=\sqrt{\frac{3kT}{m}}

We see that:

- The speed is directly proportional to the square root of the temperature

- The speed is inversely proportional to the square root of the mass of the particles

Therefore, if the two gases are at same temperature, the particles will move faster in the gas with lighter particles (smaller mass).

Since Krypton atoms have larger mass than Argon atoms, it means that atoms in Argon move faster than in Krypton.

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The mixture of rock particle sand humus is called the soil.
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2 years ago
Which statements about a sodium atom (22/11 Na ), are correct?
inysia [295]

Answer:D


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Draw the lewis structure of ch3nc; fill in any nonbonding electrons. Calculate the formal charge on each atom other than hydroge
jenyasd209 [6]

A visual representation of covalent bonding which represents the valence shell electrons in the molecule is said to be a Lewis structure. The lines represents the shared electron pairs and dots represents the electrons that are not involved in the bonding i.e lone pairs.

Number of valence electrons in each atom:

For Carbon, C = 4

For Hydrogen, H = 1

For Nitrogen, N = 5

The Lewis structure of CH_3NC is shown in the attached image.

The formula of calculating formula charge = FC = VE - NE- \frac{BE}{2}   -(1)

where, F.C is formal charge, V.E is number of valence electrons, N.E is number of non-bonding electrons and B.E is number of bonding electrons.

Now, calculating the formal charge:

For C on left side:

FC = 4 - 0- \frac{8}{2} = 0

For N:

FC = 5 - 0- \frac{8}{2} = +1

For C on right side:

FC = 4 - 2- \frac{6}{2} = -1

The formula charge of each atom other than hydrogen is shown in the attached image.


6 0
3 years ago
How to solve this: a small dog has consumed a dangerous amount of apap. the vet has ordered: rx acetylcysteine 150mg/kg/stat. yo
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Given:
Stock dose/concentration of 20% Acetylcysteine (200 mg/mL)
150 mg/kg dose of Acetylcysteine
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First we must convert 13.2 lb to kg:
13.2 lb/(2.2kg/lb) = 6 kg

Then we must calculate the dose:
(150 mg/kg)(6kg) = 900 mg

Lastly, we must calculate the dose in liquid form to be administered:
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Therefore, 4.5 mL of 20% Acetylcysteine should be given.
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3 years ago
Consider the molecule BF3. (a) What is the electron config- uration of an isolated B atom? (b) What is the electron con- figurat
anzhelika [568]

For the given molecule, we are asked to give-

  1. The electron configuration of an isolated B atom
  2. The electron configuration of an isolated F atom
  3. Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride
  4. valence orbitals, if any, remain unhybridized on the B atom.
  • The electron configuration of an isolated B atom:

as atomic number of B is 5

electronic configuration will be [He] 2s² 2p¹

  • The electron configuration of an isolated F atom:

as atomic number of F is 9

electronic configuration will be  [He] 2s² 2p5

  • Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.

as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.

  • valence orbitals, if any, remain unhybridized on the B atom will be 1

To know more about hybrisisation:

brainly.com/question/23038117

#SPJ4

8 0
1 year ago
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