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Svetach [21]
2 years ago
11

Give the conjugate base for each compound below.? Acid --- Conjugate Base H2S _________ HPO4^-2 _________ NH4+ _________ Update:

Give the conjugate acid for each compound below? Base ---- Conjugate Acid HSO4- _______ SO4^-2 _______ NH3 _______
Chemistry
2 answers:
zhenek [66]2 years ago
8 0
 <span>take away one proton from the acid to give its conjugate base. So 

HS- 

PO4^3- 

NH3</span>
svetlana [45]2 years ago
6 0

According to  Bronsted-Lowry theory acid are donor of protons and bases are acceptors of protons (the hydrogen cation or H⁺).

When acid lost proton, it forms conjugate base and when base gain proton it form conjugate acid.

1) Answer is: HS⁻.

Chemical reaction (dissotiation) : H₂S(aq) → HS⁻(aq) + H⁺(aq).

2) Answer is: PO₄³⁻.

Chemical reaction (dissotiation) : HPO₄²⁻(aq) → PO₄³⁻(aq) + H⁺(aq).

3) Answer is: NH₃.

Chemical reaction (dissotiation) : NH₄⁺(aq) → NH₃(aq) + H⁺(aq).

4) Answer is: H₂SO₄.

Chemical reaction: HSO₄⁻(aq) + H⁺(aq) → H₂SO₄(aq).

5) Answer is: HSO₄⁻.

Chemical reaction: SO₄²⁻(aq) + H⁺(aq) → HSO₄⁻(aq).

6) Answer is: NH₄⁺.

Chemical reaction: NH₃(aq) + H⁺(aq) → NH₄⁺(aq).

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The compound responsible for the characteristic smell of garlic is allicin, that is having molecular formula C₆H₁₀OS₂.

Molar mass of C₆H₁₀OS₂=162.26 g mol⁻¹.

number of moles of C₆H₁₀OS₂=1 mol

So mass of C₆H₁₀OS₂ can be calculated as:


Number of moles of C_{6}H_{10}OS_{2}, n= \frac{Given mass of the }{Molar mass of theC_{6}H_{10}OS_{2}}

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Explanation:

Different Fossil organisms succeed one another to go up through the different rock layers in a definite and determinable order. Therefore, any time period can be recognized by its fossil content

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Explain why scientists find the particulate matter of theory useful
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Firdavs [7]

Answer:

n_{Mg}=3.50molMg\\\\ n_{Cl}=7.00molCl\\\\n_O=28.0molO

Explanation:

Hello there!

In this case, according to the given information it turns out possible for us to realize that one mole of the given compound, Mg(ClO₄)₂, has one mole of Mg, two moles of Cl and eight moles of O; thus, we proceed as follows:

n_{Mg}=3.50molMg(ClO_4)_2*\frac{1molMg}{1molMg(ClO_4)_2}=3.50molMg\\\\ n_{Cl}=3.50molMg(ClO_4)_2*\frac{2molCl}{1molMg(ClO_4)_2}=7.00molCl\\\\n_O=3.50molMg(ClO_4)_2*\frac{8molO}{1molMg(ClO_4)_2}=28.0molO

Best regards!

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