Answer:

Explanation:
Given data:
Mass of mixture = 454 kg
Initial temperature is 10°C
Heat added is Q = 121300 kJ
Heat capacity (Applesuace) at 32.8°C is 4.02kJ/kg K
From heat equation we have



Putting all value to get required final temperature value


The change in the internal energy of the gas is 1.5×10∧3 J.
The internal energy of an ideal gas is directly proportional to the temperature of the gas:
ΔE = 3/2 × n × R × ΔT
ΔT = 320 K - 260 K
ΔT = 60 K; change of the temperature
n = 2.0 mol: amount of a monatomic ideal gas
R = 8.1 J/mol×K;the ideal gas constant
ΔE = 3/2 × 2 mol × 8.1 J/mol×K × 60 K
ΔE = 1500 J
ΔE = 1.5×10∧3 J; the internal energy of the gas
Isobaric process is a type of process in which the pressure of the system stays constant.
More about an isobaric process: brainly.com/question/28106078
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D= M/V so, D=300/40 wich is 7.5 so D= 7.5g/m3
Answer:
2.28 m
Explanation:
Use the relationship
λ=vf
to solve for wavelength λ. Substituting the known quantities yields:
λ=vf
λ=2.99 x 108 m/s1.31 x 108 Hz
λ=2.28 m
Filtration
hope this helped