Mass of B₂ = 18.75 g
<h3>Further explanation</h3>
Given
Element A and element B
Required
The reaction
mass of B₂
Solution
The balanced equation :
2A(s) + B₂(g) ⇒2AB(s)
mol AB :
= Molarity x Volume
= 2.5 M x 0.25 L
= 0.625
From the equation, mol ratio of B₂ : AB = 1 : 2, so mol B₂ :
= 1/2 x mol AB
= 1/2 x 0.625
= 0.3125
Mass B₂ (Molar mass = 2x30 g/mol=60 g/mol)
= mol x molar mass
= 0.3125 x 60 g/mol
= 18.75 g
Answer:
Viscosity of water decreases markedly with increasing temperature. When the viscosity decreases, the flow resistance decreases. So for the same driving force, that is the pressure drop per unit length, the water flow rate will be higher.
Hope this helps :)
Answer:
The answer to your question is V2 = 3.7 L
Explanation:
Data
Volume 1 = 3.5 L
Temperature 1 = 25°C
Temperature 2 = 40°C
Pressure = cte.
Volume 2 = ?
Formula
To solve this problem use the Charles' law
V1/T1 = V2/T2
- Solve for V2
V2 = V1T2 / T1
- Convert temperature to °K
Temperature 1 = 25 + 273 = 298°K
Temperature 2 = 40 + 273 = 313°K
- Substitution
V2 = (3.5)(313) / 298
- Simplification
V2 = 1095.5 / 298
- Result
V2 = 3.7 L
B, you can see there are 2 F atoms on each side of the equation
<span>B) The atomic orbitals overlap and share electrons to form covalent bonds. </span>
