Mm I don't know, why is that question? You must have an weird teacher
1.) 3x -4 <_ 2
Add 4 to both sides.
-4 + 4 = 0
2 + 4 = 6
3x <_ 6
Divide both sides by 3.
3x / 3 = x
6 / 3 = 2
x <_ 2 is your answer for the first inequality.
2.) 2x + 11 _> -1
Subtract 11 from both sides.
11 - 11 = 0
-1 -1 = -2
2x _> -12
Divide both sides by 2.
2x / 2 = x
-12 / 2 = -6
x _> -6 is your answer for the second inequality.
I hope this helps!
If

represent a family of surfaces for different values of the constant

. The gradient of the function

defined as

is a vector normal to the surface

.
Given <span>the paraboloid

.
We can rewrite it as a scalar value function f as follows:

The normal to the </span><span>paraboloid at any point is given by:

Also, the normal to the given plane

is given by:

Equating the two normal vectors, we have:
</span>

Since, -1 = 2 is not possible, therefore
there exist no such point <span>
on the paraboloid
such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>
.
Step-by-step explanation:
I cannot really identify and read the provided answer options.
the solution to the sequence 2, 6, 10, 14, 18, ... is
an = 4×(n-1) + 2
recursive that is
a1 = 2
an = an-1 + 4
please pick the right option in your original problem definition that fits to this solution.