I think the answer might be A and D
Step-by-step explanation:
let p be the point which is at a distance of 4 units from the x-axis and at a distance of 5 units from the y axis
(i) When P lies in the first quadrant then the coordinates of P are (5,4).
(ii) When of P lies in the second quadrant then the coordinates of P are (-5,4).
(iii) When P lies in the third quadrant then the coordinates of P are (-5,-4).
(iv) When P lies in the fourth quadrant then the coordinates of P are (5,-4).
<h3>Hope it helps you!!</h3>
Answer:
Set it up using the slope from the two points. (c - (-5))/3 - 1 = slope = (c + 5)/2. Now put this into slope intercept since they give you the y intercept of 7. y = x*(c + 5)/2 + 7. Now put in the point, (1,-5). -5 = 1*(c+5)/2 + 7. Subtract 7 from both sides. Now multiply through and you can solve for c.
Step-by-step explanation:
<span>point (3, 1) and has a slope of –2?
y-1=-2(x-3)</span>