Find the domain and the range of the relation shown on the
1 answer:
The domain of a graph is the possible values of x, the graph can take.
<em>(b) The domain of the relation is the interval [-10,10]</em>
From the attached graph, we have the following observations on the x-axis.
- <em>The value of x starts from -10</em>
- <em>The value of x ends at 10</em>
So, the domain of x is from -10 to 10
Using interval notation, the domain of the relation is:
Read more about domains at:
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Answer:
8 years
Step-by-step explanation:
Tim's account balance has an initial value of $6400 and is multiplied yearly by the factor 1.01. Thus, it can be described by the exponential equation ...
b = 6400·1.01^t
where b is the balance after t years.
Putting in the desired balance, we can find t.
6900 = 6400·1.01^t
1.078125 = 1.01^t . . . . . divide by 6400
log(1.078125) = t·log(1.01) . . . . take the logarithm of both sides
log(1.078125)/log(1.01) = t ≈ 7.56 ≈ 8 . . . . . divide by the coefficient of t
It will take Tim approximately 8 years to reach a balance of $6900.
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The problem can also be solved using a graphing calculator.
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Answer:
The recursive rule for account balance at the beginning of the nth month will be given by and
where, n = 1, 2, 3, .....
Step-by-step explanation:
On January 1, 2006, I have $100 in a savings account that earns interest at a rate of 1% per month. On the last day of every month, I deposit $75 in the account, beginning in January.
So, at the end of the month of January, the added amount to the account is $75 and 1% of $100 i.e. 1$.
Then, total $(75 + 1) = $76 is being added at the end of each month.
So, the recursive rule for account balance at the beginning of the nth month will be given by and
where, n = 1, 2, 3, ..... (Answer)