Question

A rectangular parking lot has a perimeter of 384 meters. The length of the parking lot is 36 meters less than the width. Find the length and the width.

Answer 1

Answer:

The length and width of the parking lot is 78 meters and 114 meters respectively.

Step-by-step explanation:

Given;

Perimeter of the parking lot = $384\ m$

Solution,

Let the width of the parking lot be x.

Then, according to question length = (x-36).

The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;

$perimeter=2\times(length+width)$

Now substituting the values, we get;

$384=2\times(x-36+x)\\\frac{384}{2}=(2x-36)\\192=2x-36\\192+36=2x\\2x=228\\x=\frac{228}{2}= 114$

Width = $114\ m$

Length = $x-36=114-36=78\ m$

Hence the length and width of the parking lot is 78 meters and 114 meters respectively.