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Artemon [7]
3 years ago
9

A rectangular parking lot has a perimeter of 384 meters. The length of the parking lot is 36 meters less than the width. Find th

e length and the width.
Mathematics
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

The length and width of the parking lot is 78 meters and 114 meters respectively.

Step-by-step explanation:

Given;

Perimeter of the parking lot = 384\ m

Solution,

Let the width of the parking lot be x.

Then, according to question length = (x-36).

The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;

perimeter=2\times(length+width)

Now substituting the values, we get;

384=2\times(x-36+x)\\\frac{384}{2}=(2x-36)\\192=2x-36\\192+36=2x\\2x=228\\x=\frac{228}{2}= 114

Width = 114\ m

Length = x-36=114-36=78\ m

Hence the length and width of the parking lot is 78 meters and 114 meters respectively.

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