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4 years ago

Match the correct term with the statement that is true about it:

2 answers:

6 0

ANSWER:
1. Cardiovascular Fitness
2. Muscular Fitness
3. Flexibility
4. Motivation
5. Money
6.
7. Family Behaviors
8. Understanding

is there another option for number 6? i could only find 7 word options

tino4ka555 [31]4 years ago

3 0

Answer:

1. Measure of the health of the heart and blood vessels: cardiovascular fitness

2. A weight lifter's area of expertise : muscular fitness

3. Touching your toes : flexibility

4. Learning the positive benefits of exercise : understanding

5. A limiting factor that relates to the cost of activities : money

6. A limiting factor that relates to where you live : location

7. The exercise habits that you were raised with : family behaviors

8. How you feel about yourself and your ability to excercise : motivation

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Monochromatic light is incident on a pair of slits that are separated by 0.220 mm. The screen is 2.60 m away from the slits. (As

Naddik [55]

Answer:

$\lambda = 1.667 nm$

$\theta = 0.8681^o$

Explanation:

From the question we are told that

The distance of separation is $d = 0.220 \ mm = 0.00022 \ m$

The is distance of the screen from the slit is $D = 2.60 \ m$

The distance between the central bright fringe and either of the adjacent bright $y = 1.97 cm = 1.97 *10^{-2}\ m$

Generally the condition for constructive interference is

$d sin \tha(\theta ) = n \lambda$

From the question we are told that small-angle approximation is valid here.

So $sin (\theta ) = \theta$

=> $d \theta = n \lambda$

=> $\theta = \frac{n * \lambda }{d }$

Here n is the order of maxima and the value is n = 1 because we are considering the central bright fringe and either of the adjacent bright fringes

Generally the distance between the central bright fringe and either of the adjacent bright is mathematically represented as

$y = D * sin (\theta )$

From the question we are told that small-angle approximation is valid here.

$y = D * \theta$

=> $\theta = \frac{ y}{D}$

$\frac{n * \lambda }{d } = \frac{y}{D}$

$\lambda =\frac{d * y }{n * D}$

substituting values

$\lambda = \frac{0.00022 * 1.97*10^{-2} }{1 * 2.60 }$

$\lambda = 1.667 *10^{-6}$

$\lambda = 1.667 nm$

In the b part of the question we are considering the next set of bright fringe so n= 2

Hence

$dsin (\theta ) = n \lambda$

$\theta = sin^{-1}[\frac{ n * \lambda }{d} ]$

$\theta = sin^{-1}[\frac{ 2 * 1667 *10^{-9}}{ 0.00022} ]$

$\theta = 0.8681^o$

7 0

4 years ago

While ice skating, you unintentionally crash into a person. Your mass is 60kg

miss Akunina [59]

Answer:

The speed is 6.1m/s with an angle of 56.3 degrees north of east.

Explanation:

We meed to apply the Linear momentum theorem:

$m1*vo1+m2*vo2=m1*vf1+m2*vf2\\60*(8.0m/s(East))+80*(9.0m/s(North))=140*vf\\vf=3.4m/s(East)+5.1m/s(North)$

The magnitude of the velocity is given by:

$v=\sqrt{Veast^2+Vnorth^2} \\v=6.1m/s$

and the angle:

$\alpha =arctg(\frac{Vnorth}{Veast})\\\alpha=56.3^o$

3 0

3 years ago

The Doppler effect is the apparent change in frequency due to the movement of the source and the observer. This means an object

Alekssandra [29.7K]

Answer:

Doppler effect changes the wavelength of the light emitted, depending upon whether source is moving away or coming towards the observer(detector).

Explanation:

Doppler effect in light is actually a relativistic effect but somewhat similar to the one which happens in sound waves.

When the source is moving away from the detector, the wavelength of the light emitted from the source appears to be increased as seen by the detector, as a result the frequency decreases(we know that frequency of light= speed of light/wavelength of light. Here speed of light is constant and frequency of light is inversely proportional to its wavelength)

Due to this decrease in frequency the light emitted from the source appears more red, since red color is on low frequency side in the electromagnetic spectrum.

Similarly for the source moving towards the detector, the wavelength appears to be decreased, thereby resulting in increase in frequency and the source appears blue. The shift in frequency is known as doppler shift.

The shift in frequency when the source is moving away is known as redshift and the one where the source is moving towards detector is known as blueshift

4 0

3 years ago

A car moving 20 m/s in the positive x-direction slams on the brakes and stops after skidding 20 m. what was its acceleration dur

pav-90 [236]

To find the acceleration of the car, we can use the following relationship:
$v_f^2 - v_i^2 = 2 aS$
where
$v_f=0$ is the final speed of the car (it is zero because the car comes to rest)
$v_i=20 m/s$ is the initial speed of the car
$a$ is the acceleration
$S=20 m$ is the distance covered

By rearranging the equation, we get:
$a= \frac{-v_i^2}{2 S}= \frac{-(20 m/s)^2}{2 (20 m)} =-10 m/s^2$
where the negative sign means it is a deceleration.

7 0

3 years ago

The way light reflects off a smooth surface is described by the law of reflection. This law states that the angle of reflection

matrenka [14]

Answer:

Angle of incidence ray

Explanation:

The way light reflects off a smooth surface is described by the law of reflection. This law states that the angle of reflection equals the ANGLE OF INCIDENCE RAY.

This is because, when light is reflected off a smooth surface, the light is reflected by all the points that is present on that smooth surface.

Therefore the speed at which the light rays falls on the smooth surface is the same as the speed at which the light ray is reflected back. Due to their speed been the same, the distance of the incidence ray would also be the same as the distance of the reflected ray.

Hence the angle of incidence = angle of reflection.

5 0

3 years ago

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