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Bingel [31]
3 years ago
11

What uses electricity

Physics
1 answer:
Rus_ich [418]3 years ago
5 0
Our phones, lighting ect
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What percentage of the intensity gets through both polarizers?
sp2606 [1]

Answer:

if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

Explanation:

The incident light is generally random, that is, it does not have a polarization plane, when the first polarized stops by half, this already polarized light arrives at the second polarizer and the causticity passes

                I = I₀ cos² θ

therefore if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

8 0
3 years ago
Sunlight, with an intensity of 667 W / m², strikes a flat collecting surface perpendicularly and is totally absorbed. The area o
alexandr1967 [171]

Answer:

F = 20.07 μN

Explanation:

given,                                            

intensity of sunlight = 667 W/m²

area of surface =  9.03 m²

speed of light = 3 x 10⁸ m/s

force = ?                                  

we know                                                                

force =intensity \times \dfrac{Area}{speed of light}

force =667 \times \dfrac{9.03}{3\times 10^8}

F = 20.07 x 10⁻⁶ N

F = 20.07 μN

6 0
3 years ago
Need help with physics electric question!❤️
LUCKY_DIMON [66]

The output voltage is 10 times the input voltage.

So the output coil has 10 times as many turns as the input coil has.

That's how transformers work.

Complicated, huh !

10 times 1,000 turns = <em>10,000 turns</em>

7 0
3 years ago
A steel column is 3 m long and 0.4 m diameter. It carries a load of 50 MN so that 5.967 mm is elongates more. Find the modulus o
Alex787 [66]

Answer:

E=2.0*10^{11}N/m^{2}

Explanation:

<u>Relation between stress and Force:</u>

\sigma=\frac{F}{A}=\frac{F}{\pi*d^{2}/4}

<u>Relation between stress and strain:</u>

Young's modulus is defined by the ratio of longitudinal stress σ , to the longitudinal strain ε:

E=\frac{\sigma}{\epsilon}

\epsilon=\frac{\Delta l}{l}

So:

E=\frac{F*l}{\pi*d^{2}/4*\Delta l}=\frac{50*10^{6}*3}{\pi*(0.4^{2}/4)*5.967*10^{-3}}=2*10^{11}N/m^2

8 0
3 years ago
If the work done when a charge of 5.2 × 10-13 coulombs is moved between two points is 4.7 × 10-12 joules, what is the potential
Papessa [141]
9.0, might be to late but someone in the future might need it.
3 0
4 years ago
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