Let n = 0, 1, 2, 3, 4, 5, 6, 7....
When n = 0 then 0^2 + 0 = 0. n = 1 we have 1^2 + 1 = 2. And when n = 2 we have 2^2 + 2 = 6. When n= 3 we have 3^2 + 3 = 12. When n = 4 we have 4^2 + 4 = 20. When n = 5 we have 5^2 + 5 = 30. When n = 6 = 6^2 + 6 = 42. And finally when n = 7 we have 7^2 + 7 = 56. So at n = 1, 2, ...7, ... Our values are = 2, 6, 12, 20, 30, 42, and 56. It is obvious that n is always an even number. Hence n^2 + n is always an even integer for all positive integers.
When n = -1 we have (-1)^2 - 1 = 0 when n = -2 we have (-2)^2 -2 = 2. When n = -3 we have (-3)^2 - 3 = 6. When n = -4 we have (-4)^2 - 4 = 16 - 4 =12. When n =-5 we have (-5)^2 -5 = 20. When n = -6 we have (-6)^2 - 6 = 30. When n = (-7)^2 - 7 = 42. Hence n^2 + n is always even for all integers
Step-by-step explanation:
Head(H) Tails(T)
Sample space is S (HHH,HHT,HTH,THH)
Event(HHT,HTH,THH)
so the probability is 3/4
Answer:
$255.00
Step-by-step explanation:
You can also calculate how much you save by simply moving the period in 15.00 percent two spaces to the left, and then multiply the result by $300 as follows: $300 x .15 = $45.00 savings.
notice, the first term is 9.5
from there it goes to 11.5, well, how much is it being added to get 11.5?
well 9.5 + 2, is 11.5, so it was added 2 to 9.5
then it goes from 11.5 to 13.5, namely, 11.5+2 = 13.5
and then 13.5+2 = 15.5 and so on
so, the "common difference" or the common addition value, is 2
how do you find the nth term?
well
Answer:
No
Step-by-step explanation:
Even though he has a 1/6 chance of rolling it he still has a 16.67% percent chance