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levacccp [35]
3 years ago
10

In which quadrant does 0 lie given that sin 0<0 and cos 0<0

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

\theta must be in the third quadrant so that \sin \theta < 0 and \cos \theta < 0.

Step-by-step explanation:

We have to determine that in which quadrant the angle \theta lies if \sin \theta < 0 and \cos \theta < 0.

The horizontal axis i.e. x-axis and the vertical axis i.e. y-axis divides the coordinate plane into four zones, the zone with x and y both positive is the first quadrant and rotating about the origin in anticlockwise we will find 2nd, 3rd and 4th quadrant one by one.

In the first quadrant all the trigonometrical functions \sin \theta, \cos \theta and \tan \theta are positive.

In the second quadrant only  \sin \theta is positive.

In the third quadrant only \tan \theta is positive i.e. \sin \theta and \cos \theta are negative.

In the fourth quadrant only \cos \theta is positive.

Therefore, \theta must be in the third quadrant so that \sin \theta < 0 and \cos \theta < 0. (Answer)

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OM , ON and OP are the angle bisectors of ∠AOB, ∠BOC, and ∠COD respectively. ∠AOD and ∠BOE are straight angles.
Orlov [11]

Find m∠BOC, if m∠MOP = 110°.

Answer:

m∠BOC= 40 degrees

Step-by-step explanation:

A diagram has been drawn and attached below.

  • OM bisects AOB into angles x and x respectively
  • ON bisects ∠BOC into angles y and y respectively
  • OP bisects ∠COD into angles z and z respectively.

Since ∠AOD is a straight line

x+x+y+y+z+z=180 degrees

2x+2y+2z=180^\circ

We are given that:

m∠MOP = 110°.

From the diagram

∠MOP=x+2y+z

Therefore:

x+2y+z=110°.

Solving simultaneously by subtraction

2x+2y+2z=180^\circ

x+2y+z=110°.

We obtain:

x+z=70°

Since we are required to find ∠BOC

∠BOC=2y

Therefore from x+2y+z=110° (since x+z=70°)

70+2y=110

2y=110-70

2y=40

Therefore:

m∠BOC= 40 degrees

3 0
3 years ago
A projectile is thrown upward off a 130ft cliff at a velocity of 15ft/second. How long before it reaches a height of 25ft?
zhuklara [117]

Answer:

The time taken for the projectile to reach the given height is 1.2 s.

Step-by-step explanation:

Given;

height of travel, h = 25 ft

initial velocity of the projectile, u = 15 ft/s

The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;

h = ut + ¹/₂gt²

25 = 15t + ¹/₂(9.8)t²

25 = 15t + 4.9t²

4.9t² + 15t - 25 = 0

solving the quadratic equation, we will have the following solution of t;

t = 1.2 s

Therefore, the time taken for the projectile to reach the given height is 1.2 s.

5 0
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A rectangular prism with a square base has a volume of 120 cubic feet. The base is 8 feet on each side. What is the height of th
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15feet

Step-by-step explanation: 120/8=15

pls give brainliest

3 0
3 years ago
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