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levacccp [35]
3 years ago
10

In which quadrant does 0 lie given that sin 0<0 and cos 0<0

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

\theta must be in the third quadrant so that \sin \theta < 0 and \cos \theta < 0.

Step-by-step explanation:

We have to determine that in which quadrant the angle \theta lies if \sin \theta < 0 and \cos \theta < 0.

The horizontal axis i.e. x-axis and the vertical axis i.e. y-axis divides the coordinate plane into four zones, the zone with x and y both positive is the first quadrant and rotating about the origin in anticlockwise we will find 2nd, 3rd and 4th quadrant one by one.

In the first quadrant all the trigonometrical functions \sin \theta, \cos \theta and \tan \theta are positive.

In the second quadrant only  \sin \theta is positive.

In the third quadrant only \tan \theta is positive i.e. \sin \theta and \cos \theta are negative.

In the fourth quadrant only \cos \theta is positive.

Therefore, \theta must be in the third quadrant so that \sin \theta < 0 and \cos \theta < 0. (Answer)

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A new club sent out 231 coupons to boost sales for next year's memberships. They provided 6 times as many to potential members t
grin007 [14]

Answer:

Number of coupons sent  to Existing members = 33

Step-by-step explanation:

Number of coupons sent out = 231

Let :

6 times as many to potential members = 6 * X = 6X

while existing members = X

therefore 6X + X = 231

                 7X = 231

therefore  X = 231 / 7 = 33

so existing members = 33

while potential members = 6 * 33 = 198

7 0
3 years ago
Read 2 more answers
What is the solution to <br> 2x -8 = 2(x - 4 ) ?<br><br> ALSO, explain how you solved it.
Genrish500 [490]
First, you gotta simplify. There’s really nothing to simplify so just take it out of the parenthesis.

2x-8=2x-4

Now turn the -8 into a +8. Add it on each side.

2x=2x+8

Now turn the 2x on the right into a negative. Do the same thing you did with the 8.
Now it’s:

0 = 8

That means there’s no solution.
Hope this helped :)
7 0
3 years ago
What fraction must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions
DanielleElmas [232]

Answer:

so 1/3 must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions.

Step-by-step explanation:

let the fraction be x

(1/4 + 1/6)-x =  1/12

or, 10/24 - x = 1/12

or, 5/12-1/12 = x

so, x = 4/12 = 1/3

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