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levacccp [35]
3 years ago
10

In which quadrant does 0 lie given that sin 0<0 and cos 0<0

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

\theta must be in the third quadrant so that \sin \theta < 0 and \cos \theta < 0.

Step-by-step explanation:

We have to determine that in which quadrant the angle \theta lies if \sin \theta < 0 and \cos \theta < 0.

The horizontal axis i.e. x-axis and the vertical axis i.e. y-axis divides the coordinate plane into four zones, the zone with x and y both positive is the first quadrant and rotating about the origin in anticlockwise we will find 2nd, 3rd and 4th quadrant one by one.

In the first quadrant all the trigonometrical functions \sin \theta, \cos \theta and \tan \theta are positive.

In the second quadrant only  \sin \theta is positive.

In the third quadrant only \tan \theta is positive i.e. \sin \theta and \cos \theta are negative.

In the fourth quadrant only \cos \theta is positive.

Therefore, \theta must be in the third quadrant so that \sin \theta < 0 and \cos \theta < 0. (Answer)

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Let's solve your equation step-by-step.<span><span>
98−<span>x2</span></span>=0</span>
Step 1: Simplify both sides of the equation.<span><span><span>
−<span>x2</span></span>+98</span>=0</span>
Step 2: Subtract 98 from both sides.<span><span><span><span>
−<span>x2</span></span>+98</span>−98</span>=<span>0−98</span></span><span><span>
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Step 3: Divide both sides by -1.<span><span><span>
−<span>x^2/</span></span><span>1</span></span>=<span><span>−98/</span><span>1</span></span></span><span><span>
x^2</span>=98</span>
Step 4: Take square root.<span>
x=<span>±<span>√98</span></span></span><span><span>
x=<span><span><span>7<span>√2</span></span><span> or </span></span>x</span></span>=<span>−<span>7<span>√2</span></span></span></span>
Answer:<span><span>
x=<span><span><span>7<span>√2</span></span><span> or </span></span>x</span></span>=<span>−<span>7<span>√<span>2

-Not this if this is what you wanted but I hope I helped. :)</span></span></span></span></span>
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