We have to determine that in which quadrant the angle lies if and .
The horizontal axis i.e. x-axis and the vertical axis i.e. y-axis divides the coordinate plane into four zones, the zone with x and y both positive is the first quadrant and rotating about the origin in anticlockwise we will find 2nd, 3rd and 4th quadrant one by one.
In the first quadrant all the trigonometrical functions , and are positive.
In the second quadrant only is positive.
In the third quadrant only is positive i.e. and are negative.
In the fourth quadrant only is positive.
Therefore, must be in the third quadrant so that and . (Answer)
Using the given information, we can say the following: Width (W) = x Length (L) = (2x - 4) Area of Rectangle = L × W Using this, we can formulate an equation for rectangle in question: x(2x - 4) = 30 Expand and move everything to one side: 2x² - 4x - 30 = 0 Simplify by dividing everything on both sides by 2: x² - 2x - 15 = 0 Factorise: (x + 5)(x - 3) = 0 Set each factor equal to 0 and solve for x: x + 5 = 0 x = -5 (a dimension cannot be negative so this is not the solution we want) x - 3 = 0 x = 3 (this is the solution) x = W = 3" L = 2x - 4 L = 2(3) - 4 L = 2"
So, the length the rectangle is 2" and the width is 3"