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Slav-nsk [51]
3 years ago
7

Plz help me answer the last 5 questions the first 3 pics is the article to help answer the question I have very little time so I

need this asap

Mathematics
1 answer:
nadezda [96]3 years ago
4 0
The papers are to blurry hard to read cdn you repost them
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Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of
Alexxx [7]

Answer:

a) 0.018

b) 0            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)

= 1 - P(z \leq 2.1)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%

0.018 is the probability that if an individual man is randomly​ selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected​ men, these men have a mean hip breadth greater than 16.5 in)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(x > 16.5)  

P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)  

= 1 - P(z \leq 23.29)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 1 = 0

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

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The correct answer is y-axis, x-axis, y-axis, x-axis.

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Antoinette solves the linear equation 3(x-3)+2x+9=2x+2(x-1)
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Hope this worked :3

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The tree is 8 feet tall.

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Mr. Chen gave a history test to his class. The scores are shown below. 75 62 68 81 55 92 58 88 72 82 48 93 81 85 77 He plotted t
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82 I think that’s the answer because that’s my opinion if it’s wrong I don’t know what to tell you
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