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Kaylis [27]
3 years ago
15

Given that P = (-5, 5) and Q = (-13, 10), find the component form and magnitude of 2 vector PQ.

Mathematics
2 answers:
Brut [27]3 years ago
4 0
Define unit vectors along the x-axis and the y-axis as \hat{i} , \, \hat{j} respectively.

Then the vector from P to Q is
\vec{PQ} = (-13+5)\hat{i} + (10-5)\hat{j} = -8\hat{i} + 5\hat{j}
In component form, the vector PQ is (-8,5).

The magnitude of vector PQ is
√[(-8)² + 5²] = √(89) = 9.434

Answer:
The vector PQ is (-8, 5) and its magnitude is √89  (or 9.434).
algol [13]3 years ago
3 0

Answer:

<-16, 10>, square root of 178

Step-by-step explanation:

The other user was close, BUT he forgot to multiply his work by 2, and there were a few miscalculations.

The formula to find PQ respectively is <q1-p1,q2-p2> (Note: if they ask you to find QP then just flip the formula to <p1-q1,p2-q2>)

-13-(-5)=-8

10-5=5

Multiply them by 2 to get <-16,10>

To get the magnitude you use the same formula for the first part before, then you square both of them and add them together, then take the square root.

-13-(-5)=-8

-8^2=64

10-5=5

5^2=25

64+25=89

89*2=178

Take the square root: (square root of 178)

Then your done!

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one number is equal to the square of another. find the numbers if both are positive and their sum is 1122
statuscvo [17]

Answer:

One number is 561

The other number is 23.6854

Step-by-step explanation:

x = y^2                One number = the square of another

x + y^2 = 1122     The sum of the two numbers is 1122

Substitute y^2 in for x on the second equation.

y^2 + y^2 = 1122    Combine like terms on the left

2y^2 = 1122            Divide by 2

y^2 = 1122/2

y^2 = 561                Take the square root of both sides.

y = 23.6854            

x = y^2

x = 561

y^2 = 561


4 0
3 years ago
PLEASE HELP WILL MARK THE BRAINLIEST
goldfiish [28.3K]

Answer:

12

Step-by-step explanation:

26+(-2)=24

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8 0
2 years ago
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