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yan [13]
3 years ago
12

In right ∆ABC the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find BC if AD = 8 cm and DH = 4 cm.

Mathematics
2 answers:
Allushta [10]3 years ago
6 0

Answer:

AB=16 \sqrt{3}   AC =8\sqrt{3}  BC=24

Step-by-step explanation:

alina1380 [7]3 years ago
5 0
Check the picture below.

notice that the triangle ADH, since the segment AL is an angle bisector, meaning  it cuts the angle A in two equal halves, then the triangle ADH is only using half of A.

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15. (-4-3)/(-5-0)= -7/-5= 7/5

      y - 3 = 7/5x - 0

      y = 7/5x + 3

16. (-2-3)/(4-0)= -5/4

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17. (-3+5)/(0+3)= 2/3

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18. (-2-2)/(0+4)= -4/4= -1

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       y - 2 = -x - 4

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19. y - 3 = 1/2x - 0

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20. y - 2 = -(x + 1)

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23. perp. 3/4

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   y = 3/4x - 2

24. perp. 7/5

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 y = 7/5x - 3

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3 years ago
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