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lions [1.4K]
3 years ago
6

The following triangle ABC is rotated clockwise about the origin the new coordinates are A'(1,-2) B'(4,6) and C'(-2,3). Which of

the following is measured of the angle of rotation?
Original Angles A(2,1) B(-6,4) C(-3,-2)


A. 45 degrees

B. 90 degrees

C. 180 degrees

D. 270 degrees
Mathematics
2 answers:
Yanka [14]3 years ago
5 0
B.90 because 90 degrees is above the original angel
Setler [38]3 years ago
3 0
The answer is B!!!!!!!
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Erin had 55 stuffed bears. She took out her 7 favorite and equally divided the rest among her 3 sisters. How many bears did each
m_a_m_a [10]

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16

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5 0
2 years ago
Solve the equation using the quadratic formula : x^2-10x+25=18
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x^2-10x+25=18 \\ \\x^2-10x+25-18 = 0\\ \\ x^2-10x+ 7 =0 \\ \\a=1 , b = -10 , c= 7 \\ \\ \Delta = b^{2}-4ac = (-10)^{2}-4*1*7=100-28 = 72 \\ \\\sqrt{\Delta }=\sqrt{72}= \sqrt{2*36} =\sqrt{36}*\sqrt{2} =6\sqrt{2}

x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- 6\sqrt{2}}{2}=\frac{2(5-3\sqrt{2})}{2}= 5-3\sqrt{2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ 6\sqrt{2}}{2}=\frac{2(5+3\sqrt{2})}{2}= 5+3\sqrt{2}


Answer : \ x= 5-3\sqrt{2} \ \ or \ \ x = 5+3\sqrt{2}


8 0
3 years ago
A square pool has a side length of x feet.A uniform border around pool is 1 footwide.The total area of the pool and the border o
lions [1.4K]
The total area of pool and border = 361  square feet.

Length of square pool = x

Length of square pool plus border =  (x + 1 +1 ) = x + 2

There is 1 foot length on each side on the x  length.

The other length of the square pool and border =  (x + 2)

Area = (x+2)(x+2)

     (x + 2)(x +2) =  361.            Let A = x +2

        A*A = 361
            A²  = 361    Take square root of both sides
             A  = √361
               A = 19

A = x + 2 = 19
       x = 19 - 2
       x = 17

Area of square pool = x*x = 17*17 = 289

Area of the pool = 289 square feet.
8 0
2 years ago
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