Answer:
The last 2 statements are true
Step-by-step explanation:
given f(x) = x² + 6x and g(x) = 2x³
f(x) × g(x) = 2x³(x² + 6x) = 2
+ 12
not 2 + 12x³
f(0) = 0 + 0 = 0 and g(2) = 2 × 2³ = 2 × 8 = 16
f(0 × g(0) = 0 × 16 = 0 ≠ 16
f(1) = 1 + 6 = 7 and g(1) = 2 × 1³ = 2
f(1) × g(1) = 7 × 2 = 14 ← True
g(x) × g(x) = 2x³ × 2x³ = 4
= 4
← True
To find the x-intercept you must make y=0
3x+2y=12 - substitute 0 for y
3x+2(0)=12 - multiply 2 and 0
3x+0=12 - add zero
3x=12 - divide by 3
x=4
To find the y-intercept you must make x=0
3x+2y=12 - substitute 0 for x
3(0)+2y=12 - multiply 3 and 0
0+2y=12 - add 0 and 2y
2y=12 - divide by 2
y=6
Answer:
x= -2, y = -3
Step-by-step explanation:
1. substitute x = 4+2y in the first equation: 
simplify it : 
2. isolate y in 8 + 5y = -7 --> 5y = -7 - 8 -->
3. solve for y: 5y = -15 --> y = -15/5 --> y= -3
4. solve for x: x = 4 + 2y
x = 4 + 2(-3)
x = 4 + (-6)
x = -2
Could you zoom out a little maybe? it looks like you cut off something in front of dot
10+8/2-4
PEMDAS
parenthasese
exxonents
multiplication or division
addiotn or subtration next
10+8/2-4
8/2 first
4
10+4-4
add
10+4=14
minus
14-4=10
answer is 10
