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Serjik [45]
3 years ago
13

An airplane undergoes the following displacements, all at the same altitude: First, it flies 59.0 km in a direction 30.0° east o

f north. Next, it flies 58.0 km due south. Finally, it flies 100 km 30.0° north of west. Use components to determine how far the airplane ends up from its starting point.A) 70.1 km B) 71.5 km C) 68.7 km D) 74.4 km E) 73 km

Physics
1 answer:
ddd [48]3 years ago
7 0

Answer:

B) 71.5 [km]

Explanation:

To solve this problem we will decompose each of the directions in the x & y axes.

To solve this problem we will decompose each of the directions in the x & y axes. also for a greater understanding of the angles, you should look at the attached image, which contains the orientations for each angle (clockwise or counterclockwise).

<u>59.0 km in a direction 30.0° east of north</u>

<u />

d_{1x}= 59*sin(30) = 29.5[km]\\d_{1y}= 59*cos(30) = 51.09[km]

<u>58.0 km due south</u>

<u />

d_{2y} = - 58 [km]\\

<u>It flies 100 km 30.0° north of west</u>

<u />

<u />d_{3x}= - 100*cos(30) = -86.6[km]\\d_{3y} = 100*sin(30)= 50 [km]<u />

<u />

Now we sum algebraically the components

d_{x}=29.5-86.6 = -57.1[km]\\d_{y}=51.09 -58+50=43.09[km]\\\\

Using the Pythagorean theorem we can find the magnitude of the displacement.

d = \sqrt{(57.1)^{2} +(43.09)^{2} } \\d= 71.53[km]

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Answer:

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Explanation:

So, we are given the following data or parameters or information in the following questions;

=> "A jet transport with a landing speed

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We are also give that the "aerodynamic forces on the aircraft are small and may be neglected at lower speed"

Step one: determine the acceleration;

=> Acceleration = 1/ (2 × distance along runway with constant deceleration) × { (landing speed A)^2 - (landing speed B)^2 × 1/(3.6)^2.

=> Acceleration = 1/ (2 × 425) × (200^2 - 60^2) × 1/(3.6)^2 = 3.3 m/s^2.

Thus, "the reaction N under the nose wheel B toward the end of the braking interval and prior to the application of mechanical braking" = The total mass of the aircraft × acceleration × 1.2 = 15N - (9.8 × 2.4 × 140).

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4 0
3 years ago
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The difference in energy for n = 1 to n = 4 is:

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4 0
3 years ago
Read 2 more answers
: 1 khối khi lý tưởng nhận được nhiệt lượng 200J, khi đó khí nở ra đẩy pittong bằng 1 công 80J.
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Answer:

DU = 120 Joules

Explanation:

Given the following data;

Quantity of energy = 200 J

Work = 80 J

To find the change in internal energy;

Mathematically, the change in internal energy of a system is given by the formula;

DU = Q - W

Where;

DU is the change in internal energy.

Q is the quantity of energy.

W is the work done.

Substituting into the formula, we have;

DU = 200 - 80

DU = 120 Joules

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