Question

A baseball player hits a ball at an angle of 52 degrees and at a height of 4.8 ft. if the ball's initial velocity after being hit is 150 and if no one catches the ball when will it hit the ground?

Answer 1

The vertical velocity of the ball is: $(150\frac{ft}{s})(sin52) = 118.2\frac{ft}{s}$. Since gravity acts at $-32\frac{ft}{s^2}$, this means that the time of flight up to the maximum height (at which vertical velocity is 0) would be:

$(0 - 118.2)=(-32)t \\ t = 3.69 s$
This maximum height is:
$4.8 + 118.2t + 0.5(-32)t^2 \\ = 4.8 + 118.2(3.69) - 16(3.69)^2 \\ = 223.1 ft$
Then the time for it to fall down will be:

$0.5(-32)(t_{2})^2=-223.1 \\ t_2 = 3.73s$
The total time will be 3.69 + 3.73 = 7.42 seconds.

Answer 2

Answer:

C. 7.43

Explanation: