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sesenic [268]
3 years ago
13

A baseball player hits a ball at an angle of 52 degrees and at a height of 4.8 ft. if the ball's initial velocity after being hi

t is 150 and if no one catches the ball when will it hit the ground?
Physics
2 answers:
Natalija [7]3 years ago
8 0
The vertical velocity of the ball is: (150\frac{ft}{s})(sin52) = 118.2\frac{ft}{s}. Since gravity acts at -32\frac{ft}{s^2}, this means that the time of flight up to the maximum height (at which vertical velocity is 0) would be:

(0 - 118.2)=(-32)t \\ t = 3.69 s
This maximum height is:
4.8 + 118.2t + 0.5(-32)t^2 \\ = 4.8 + 118.2(3.69) - 16(3.69)^2  \\ = 223.1 ft
Then the time for it to fall down will be:

0.5(-32)(t_{2})^2=-223.1 \\ t_2 = 3.73s
The total time will be 3.69 + 3.73 = 7.42 seconds.
enot [183]3 years ago
7 0

Answer:

C. 7.43

Explanation:

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<h2>Option 2 is the correct answer.</h2>

Explanation:

Elastic collision means kinetic energy and momentum are conserved.

Let the mass of object be m and M.

Initial velocity object 1 be u₁,  object 2 be u₂

Final velocity object 1 be v₁,  object 2 be v₂

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We have

            Initial momentum = Final momentum

            24 = 3v₁ + 6M

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            Initial kinetic energy = Final kinetic energy

            96 = 1.5 v₁² + 18 M

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Substituting  v₁ = 8 - 2M

           (8 - 2M)² + 12 M = 64    

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            4M² = 20 M

               M = 5 kg

Option 2 is the correct answer.  

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