Jupiter, the largest planet in the solar system, has an equatorial radius of about 7.1 x 10^4km (more than 10 times that of Eart
1 answer:
Answer:
The average speed is
The average speed is different from the average velocity in this question
Explanation:
From the question we are told that
The equatorial radius of Jupiter is
The period of oscillation of Jupiter is
Generally the average speed is mathematically represented as
=>
=>
Generally in average speed the direction is not considered while in average velocity the direction is considered for the case of this question the movement equitorial point has no direction in that it start from one point and after its periodic motion it still remains at that point
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Minimum diameter is required for the wire is 1.2X10⁻³m.
Tensile force, which consists of tensile stress and tensile strain, is the stretching force exerted on the material. This indicates that the forces are attempting to stretch the material that is subject to the force since it is under tension.
Given;
Tensile force (ft) = 780 N
length (l) = 3.00 mm
change in length (Δl) = 0.25 cm
determine the strain ε = Δl/l
determine the stress σ = Eε = E(Δl/l)
determine the cross-sectional area A = f/σ = ft/EΔl
determine the diameter d = 2 =
take Young's modulus for steel E=200 GPa, Substitute the values,
d = = 1.2X10⁻³
minimum diameter is required for the wire is 1.2X10⁻³m.
Learn more about the Tensile force with the help of the given link:
#SPJ4
I understand that the question you are looking for is "A circular steel wire 3.00 cm long must stretch no more than 0.25 cm when a tensile force of 780 N is applied to each end of the wire. What minimum diameter is required for the wire?"
Answer:
a)6.7m/S
b)6.8m/s
Explanation:
Hello ! To solve the point b you must follow the steps below
1.Draw the slide taking into account its length and height and find the angle from which the swimmer is launched (see attached image)
2. Find the horizontal velocity (X) and vertical (Y) components (see attached image)
3) for the third step we must remember that as in the slide there is no horizontal acceleration the speed in X will remain constant at the end of the swimmer's path (Vx = 0.59m / s)
4)
the fourth step is to remember that vertically there is constant acceleration called gravity (g = 9.81m / s ^ 2), so to find the speed at the end of the route we use the following equation
where
Vfy= final verticaly speed
Vy=initial verticaly speed=0.59m/S
g=gravity=9.81m/S^2
y=height of slide=2.31m
solving
The last step is to add the velocity components vectorally at the end of the route with the following equation
point A
taking into account the previous steps we can infer that as the swimmer starts from rest, the velocity (Vx=Vy=O) is zero, so we should only use the formula for constant acceleration movement.
vy=0
Vfy==6.7m/s
