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Fiesta28 [93]
4 years ago
8

John stretched while his muscles were cold. Which negative effect could occur?

Physics
2 answers:
Ede4ka [16]4 years ago
5 0

Answer:

The answer for Plato is C.

Genrish500 [490]4 years ago
3 0
<h3><u>Answer;</u></h3>

C) He could injure or pull a muscle.

<h3><u>Explanation</u>;</h3>
  • <em><u>When muscles are stretched the muscle fibers are temporary lengthened. Muscles have a unique ability to undergo contraction and lengthening since they are elastic.</u></em>
  • <em><u>When the muscles are warm they are more elastic, therefore, warming up the muscles is very important for the purpose of avoiding injuries.</u></em> Ir is important to engage in moderate cardiovascular warm-up prior to stretching, which increases the blood flow to the active and thus avoiding injuries to the muscles.
  • Stretching muscles when they are cold may bring injuries or cause muscle pulls, which are painful.
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to move a heavy object, like a refrigerator which one of the following would not help to decrease the friction force?
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Use round wheels to roll the heap, help the weight by evacuating appended or contained protests, or place a smoother surface betwen the question and the floor. Water or different liquids can be utilized to diminish the protection, yet just on the off chance that they stay between the question and the floor.
8 0
3 years ago
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The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32.50 N/m, is 0.640 J. Find by how
liraira [26]

Answer:

A

   x = 0.198456 \ m

B

    h  =  1.3061 \  m

C

 v =  5.06 \  m/s

D

  d = 4.0273 \  m

Explanation:

Considering the first question

From the question we are told that

   The spring constant is  k  =  32.50 N/m

    The potential energy is  PE  =  0.640 \ J

Generally the potential  energy stored in spring  is mathematically represented as   PE  =  \frac{1}{2}  *  k  *  x^2

=>    0.640=  \frac{1}{2}  * 32.50  *  x^2  

=>    x = \sqrt{0.03938}  

=>    x = 0.198456 \ m  

Considering the second question

 From the question we are told that

   The mass of the dart is  m =  0.050 kg

Generally from the law of energy conservation

         PE =  mgh

=>       0.640   =  0.050 *  9.8  *  h

=>      h  =  1.3061 \  m

Considering the third  question

   The height at which the dart was fired horizontally is  H  =   3.90\  m

Generally  from the law of energy conservation

         PE = KE

Here  KE is kinetic energy of the dart which is mathematical represented as

     KE  =  \frac{1}{2}  *  mv^2

=>      0.640 =  \frac{1}{2}  * 0.050 *  v^2

=>       v^2 = 25.6

=>       v =  5.06 \  m/s

Considering the fourth question

Generally the total time of flight of the dart is mathematically represented as

       t  =  \frac{ 2 *  H }{g}

=>     t  =  \frac{ 2 * 3.90 }{9.8 }

=>     t  =  0.7959 \ s

Generally the  horizontal distance from the equilibrium position to the ground is  mathematically represented as

       d =  v  *   t

=>     d = 5.06  *   0.7959

=>     d = 4.0273 \  m

5 0
3 years ago
The gravitational acceleration is 9.81 m/s2 here on Earth at sea level. What is the gravitational acceleration at a height of 35
azamat

To solve this problem it is necessary to apply the definition of severity of Newtonian laws in which it is specified that gravity is defined by

g= \frac{GM}{R^2}

Where

G= Gravitational Constant

M = Mass of Earth

R= Radius from center of the planet

According to the information we need to find the gravity 350km more than the radius of Earth, then

g_{ss} = \frac{GM}{R+h^2}

g_{ss} = \frac{6.67*10^{-11}*5.972*10^{24}}{(6371*10^3+350*10^3)^2}

g_{ss} = 8.82m/s^2

Therefore the gravitational acceleration at 350km is 8.82m/s^2

5 0
3 years ago
Under which condition would time periods of daylight and darkness be equal everywhere on Earth all year? A. if Earth revolved ar
FromTheMoon [43]
The answer is b because that is the correct one
8 0
3 years ago
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What explains the key difference between a bomb calorimeter and a coffee cup calorimeter?.
Virty [35]

The key difference between a bomb calorimeter and a coffee cup calorimeter is high temperature.

<h3>What is bomb calorimeter?</h3>

A bomb calorimeter is an apparatus that can measure heats of combustion, used in various applications such as calculating the calorific value of foods and fuels.

<h3>What is coffee cup calorimeter?</h3>

A coffee cup calorimeter is a cup used to provide insulation when materials are mixed inside of it.

<h3>Difference between the two calorimeter</h3>
  • The coffee cup calorimeter can't be used for high-temperature reactions, either, because they would melt the cup.
  • A bomb calorimeter is used to measure heat flows for gases and ​high-temperature reactions

Learn more about calorimeter here: brainly.com/question/1407669

#SPJ1

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