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tatuchka [14]
3 years ago
11

A car traveling west in a straight line on a highway decreases its speed from 30 meters per second to 23 meters per second in 2

seconds. The car's average acceleration during this time interval is
Physics
2 answers:
garik1379 [7]3 years ago
6 0
U1= 30m/s
u2= 23m/s
t=2s
a=(u2-u1)/t
a=-7/2=-3.5 m/s^2
mihalych1998 [28]3 years ago
3 0
Use the equation Vf=Vi+A(t)
Rearrange it so A is isolated: A= Vf-Vi/t
A=(23-30)/2
A=-3.5m/s^2
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madam [21]

Answer:

μ=0.151

Explanation:

Given that

m= 3.5 Kg

d= 0.96 m

F= 22 N

v= 1.36 m/s

Lets take coefficient of kinetic friction = μ

Friction force Fr=μ m g

Lets take acceleration of block is a m/s²

F- Fr = m a

22 -  μ x 3.5 x 10 = 3.5 a         ( take g =10 m/s²)

a= 6.28 - 35μ  m/s²

The final speed of the block is v

v= 1.36 m/s

We know that

v²= u²+ 2 a d

u= 0 m/s given that

1.36² = 2 x a x 0.96

a= 0.963 m/s²

a= 6.28 - 35μ  m/s²

6.28 - 35μ = 0.963

μ=0.151

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3 years ago
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4 years ago
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Y_Kistochka [10]

To solve this problem we will apply the concept of current defined as the electron charge flow by the number of electrons per second. That is,

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A the same time the power is described as the applied voltage for the current.

P = VI

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And the power in the Beam is

P = VI

P = (350*10^3)(0.1602)

P = 0.05607 Watts

3 0
3 years ago
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