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3 years ago

The chart shows the voltage of four electric currents.

Chemistry

2 answers:

masha68 [24]3 years ago

7 0

Answer: The correct option is Current W flows at a higher rate than Current Z.

Explanation: To answer this question, we will require Ohm's law.

Ohm's Law states that the current flowing through a conductor across two points is directly proportional to the voltage difference across that two points.

Mathematically,

$V=IR$

where, V = voltage

I = Current

R = resistance

For the given question, assuming that the resistance is constant. So, the current is directly proportional to the voltage.

$V\propto I$

Hence, as the current W is greater of all the given currents so, it will flow at a higher rate.

Therefore, the correct answer is Current W flows at a higher rate than Current Z.

masya89 [10]3 years ago

4 0

Answer:

Explanation:

Current X has a lower potential difference than Current Y.

Took test on edge 2020.

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If 1.00 mol of argon is placed in a 0.500-L container at 27.0 degree C , what is the difference between the ideal pressure (as p

ElenaW [278]

Answer:

2.0 atm is the difference between the ideal pressure and the real pressure.

Explanation:

If 1.00 mole of argon is placed in a 0.500-L container at 27.0 °C

Moles of argon = n = 1.00 mol

Volume of the container,V = 0.500 L

Ideal pressure of the gas = P

Temperature of the gas,T = 27 °C = 300.15 K[/tex]

Using ideal gas equation:

$PV=nRT$

$P=\frac{1.00 mol\times 0.0821 L atm/mol K\times 300.15 K}{0.500 L}=49.28 atm$

Vander wall's of equation of gases:

The real pressure of the gas= $p_v$

For argon:

$a=1.345 L^2 atm/mol^2$

b=0.03219 L/mol.

$(p_v+(\frac{an^2}{V^2})(V-nb)=nRT$

$(p_v+(\frac{(1.345 L^2 atm/mol^2)\times (1.00 mol)^2}{(0.500 L)^2})(0.500 L-1.00 mol\times 0.03219L/mol)=1.00 mol\times 0.0821 L atm/mol K\times 300.15 K$

$p_v = 47.29 atm$

Difference : $p - p_v= 49.28 atm - 47.29 atm = 1.99 atm\approx 2.0 atm$

2.0 atm is the difference between the ideal pressure and the real pressure.

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3 years ago

A solution of an enzyme normally found in the human body was added to a flask containing a solution of proteins in distilled wat

xenn [34]

<h3><u>Answer;</u></h3>

increase the temperature from 27 degrees celsius to 37 degrees celsius

<h3><u>Explanation;</u></h3>

The rate of an enzyme-catalyzed reaction increases as the temperature is raised.
<em><u>The human body is maintained at 37°C as this is the temperature at which the enzymes in our body work best. Therefore increasing the temperature from 27 degrees Celsius to 37 degrees Celsius increases enzyme activity and in turn increases the production of amino acid in the flask.</u></em>
Higher temperatures than 37° C which is the optimum temperature, disrupt the shape of the active site, which will reduce enyzme activity, or prevent it from working, in other words the enzyme will have been denatured.

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3 years ago

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Aleksandr [31]

Answer:

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