Answer:
B. O₂
Explanation:
First we <u>convert 192 g of O₂ into moles</u>, using its <em>molar mass</em>:
- 192 g ÷ 32 g/mol = 6 mol O₂
Now we <u>calculate with how many CS₂ moles would 6 moles of O₂ react with</u>, using the <em>stoichiometric coefficients</em>:
- 6 mol O₂ * = 2 mol CS₂
As there are 4.50 moles of CS₂ and only 2 moles would react, CS₂ is in excess and O₂ is the limiting reactant.
The correct answer is option B.
Answer:
What are three ways continents get bigger?
age of rocks.
fossils.
evidence of melting (subduction)
location on current continents.
glacial deposits.
Start by looking to the product there that doesn't have coefficient. Need to have exactly 2 Fe on the reactant side. So first coefficient is 2.. having a 2 there gives 2*3 = 6 H on the reactant side. Then in order to have 6 H on the product side the coefficient there needs to be 3. This gives 3 Ca on product side so there must be 3 Ca on reactant side.
coefficients:
2 + 3 --> 1 + 3
Where are the answer choices?
Answer:
- <u><em>The volume of CO₂(g) produced at STP when 0.05 moles of C₂H₄(g) was burnt in O₂(g) is 2.24dm</em></u><em><u>³</u></em>
Explanation:
The question is incomplete.
This is the complete question:
<em>Consider the reaction by the following equation:</em>
<em />
<em> C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)</em>
<em />
<em>The volume of CO₂(g) produced at s.t.p when 0.05 moles of C₂H₄(g) was burnt in O₂(g) is ________</em>
<em />
<em>[Molar Volume of gas = 22.4dm³]</em>
<em />
<em> A. 1.12dm³</em>
<em> B. 2.24dm³</em>
<em> C. 3.72dm³</em>
<em> D. 4.48dm³</em>
<h2>Solution</h2>
<u />
<u>1. Write the mole ratio between CO₂(g) and C₂H₄(g)</u>
- 1 mol C₂H₄(g) : 2 mol CO₂(g)
<u>2. Multiply the 0.05 moles of C₂H₄(g) by the mole ratio</u>
- 0.05 mol C₂H₄ × 2 mol CO₂ / 1 mol C₂H₄(g) = 0.10 mol CO₂
<u>3. Convert moles of CO₂ to volume at STP using the molar volume at STP</u>
- 0.10 mol CO₂ × 22.4 dm³ / mol = 2.24 dm³