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3 years ago

Jenna’s weight changed by -3 kg last month. Sarah’s weight changed by 2 1/2kg last month who lost more weight?

Mathematics

1 answer:

Law Incorporation [45]3 years ago

4 0

Hello, I'll try to make this as easy to understand as possible, anyways, let's begin:

First, we know that 3 is a bigger number than 2 1/2, and since it's negative, it means they lost weight, therefore...

Jenna lost more weight than Sarah.

Hope this helped! c:

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Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

3 0

2 years ago

Subtitute 2x+y=7 and 3x-y=8

iogann1982 [59]

Answer:

x = 3 , y = 1

Step-by-step explanation:

2x + y = 7

3x + y = 8

solution

2x + y = 7-----------(1)

3x - y = 8------------(2)

from equation 1

2x + y = 7

y = 7 - 2x-------------(3)

substitute equation 3 into equation 2

3x - y = 8

3x - (7 - 2x) = 8

3x - 7 + 2x = 8

3x + 2x = 8 + 7

5x = 15

divide through by the coefficient of x

5x/5 = 15/5

x = 3

to find y

substitute x into equation 1

2x + y = 7

2(3) + y = 7

6 + y = 7

y = 7 - 6

y = 1

8 0

3 years ago

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