Answer:
The correct answer is option a.
Explanation:
Moles of octane =
Moles of oxygen gas =
According to reaction, 25 moles of oxygen reacts with 2 moles of octane.
Then 0.46875 moles of oxygen will react with:
of octane
Oxygen is present in limited amount. Hence, limiting reagent.
According to reaction , 25 moles of oxygen gives 16 moles of carbon-dioxide.
Then 0.46875 moles of oxygen will give:
of carbon-dioxide
Mass of 0.3 moles of carbon-dioxide:
0.3 g × 44 g/mol = 13.2 g
Theoretical yield = 13.2 g
Experimental yield = x
Percentage yield of carbon dioxide = 93 %
x =12.27 g ≈ 12 g
12 grams of carbon dioxide will be produced in this engine .
<span>D) Electrons flow because of electrical attraction and repulsion</span>
Answer:
[H3O+] = 1.0*10^-12 M
[OH-] = 0.01 M
Explanation:
We can use the following equation to find the hydronium ion concentration. Plug in the pH and solve for H3O+.
pH = -log[H3O+]
<u>[H3O+] = 1.0*10^-12 M</u>
Now, to find the hydroxide ion concentration we will use the two following equations.
14 = pH + pOH
pOH = -log[OH-]
14 = 12 + pOH
pOH = 2
2 = -log[OH-]
<u>[OH-] = 0.01 M</u>
The answer to this question is: The pressure will be increased two times
The gas law includes an interaction of pressure(p), volume(V) and temperature(T). In this case, the gas has same amount and volume but then the temperature is doubled. The calculation would be:
p1 * V1 / T1= p2*V2 /T2
p1 * 1 / 1 = p2 * 1 / 2
p1 / (1/2)=p2
p2= 2* p1