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3 years ago

An atom has 23 protons and 29 neutrons. Which is the correct chemical symbol for this atom?

Chemistry

2 answers:

Gnoma [55]3 years ago

5 0

The symbol for this element is <span>V </span>, which is the well-known element vanadium.

Alex787 [66]3 years ago

4 0

Answer:

Chemical symbol is 'V'

Explanation:

No. of protons = 23

No. of protons = Atomic number

So, the atomic number of the element = 23

Mass number = No. of protons + No. of neutrons

= 23 + 29

= 52

Elements with atomic number 23 and mass number 52 is vanadium.

Chemical symbol of vanadium is 'V'.

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Water and phosphorus with a total mass of 200 grams are added to a flask like the one below and then the flask is sealed with a

ohaa [14]

Answer:

h20 o3vbjbxhnnhbnkknnchemesry

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3 years ago

C-12, c-13, and c-14 have the same number of protons but different numbers of neutrons so they are

laiz [17]

Atoms with the same number of protons, but different numbers of neutrons are isotopes of the same element.

6 0

3 years ago

How much mass does 1 mol of O2 gas have?

cluponka [151]

Answer: 15.99 x2g

Explanation:

8 0

3 years ago

On the basis of the information below, the dissolution of FeF2(s) in acidic solution is A. thermodynamically favorable, because

antoniya [11.8K]

Since K3 is greater than 1, the reaction is thermodynamically favorable.

Data;

FeF2 is in an acidic solution
K2 > 1 is thermodynamically favorable
k3 > 1 is not thermodynamically favorable
K1<1 is not thermodynamically favorable

This states that the heat change in a given chemical reaction is the same irrespective of the number of process in which the reaction is effected.

Using Hess Law;

$rxn_3 = rxn_1 * 2rxn_2\\k_3 = k_1 * k_2^2\\k_3 = 2*10^-^6 * (1*10^3)^2\\k_3 = 2$

substituting this using Gibbs law,

$\delta G^0_3 = -RT\ln K_3\\\delta G^0_3 < 0$

Since K3 is greater than 1, the reaction is thermodynamically favorable.

Learn more on Hess law here;

brainly.com/question/12895682

8 0

2 years ago

Please Help!!

dexar [7]

Mass of N₂ will be formed : 50.12 g

<h3>Further explanation</h3>

Reaction

2 NH₃(g) + 3 CuO(s) → N₂(g) + 3 Cu(s) + 3 H₂O(g)

moles NH₃ = 3.58

ratio mol NH₃ : mol N₂ = 2 : 1

so mol N₂ :

$\tt \dfrac{1}{2}\times 3.58=1.79$

mass N₂ (MW=28 g/mol) :

$\tt 1.79\times 28=50.12~g$

7 0

3 years ago