First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2
Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
Answer:
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Explanation:
15.0 cm(1 m/100 cm) = 0.150 m Always include your units so you can tell what your final units will be.
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Answer:
D) 4.97M
Explanation:
firstly we will calculate the molar mass of K2HPO4.
K=39, H=1 , P=31, O=16
K2HPO4 = (39*2)+(1)+(31)+(16*4) =174g/mol
number of moles = mass / molar mass
mass of K2HPO4 =238g
number of moles = 
moles.
moles is contained in 275mL of solution.
The molarity of a solution is the number of moles of solute contained in 1000mL of solution.
if moles is contained i 275mL of solution
Then X will be contained in 1000 mL of solution
x=4.9739moles
x ≈ 4.97moles
4.97moles is contained in 1000mL of solution.
The molarity of the solution is 4.97M
Chemical bonds are bonds that stay securely in place. Without those types of things, we would never know as many elements as we do today.
