Can you give more explanation <span />
Step 1 is to factor everything!
After factoring you will get:
x-5 over (x+2)(x+5) times x+4 over (x-3)(x+4)
Step 2 is to remove the duplicate factors!
Remove x+4 and x+5
x-5 over (x+2)(x-5) times 1 over x-3 = 1 over x+2 times 1 over x-3
Step 3 is to multiply the numerators and the denominators.
End result is 1 over (x+2)(x-3)
Answer:
It's B and E
Step-by-step explanation:
Answer:
0.6708 or 67.08%
Step-by-step explanation:
Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:
There is a 0.6708 probability that Helen makes both free throws.
X = kp/y-c
cross multiply
xy-xc = kp
factor out the x
x(y-c) = kp
divide entire equation by x
y-c = kp/x
isolate y since we are solving for y
we do this by adding c to both sides which ultimately gives us the answer
y = kp/x + c
