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Triss [41]
3 years ago
14

Help I need help please!

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

Step-by-step explanation:

one of them is gonna be alot lighter than the rest so i guess use intuition to find it and then measure its weight. ion have a clue what i just said :(

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Help help help pls :)
kykrilka [37]

Answer:

opposite\approx 70.02

Step-by-step explanation:

The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}

Please note that the names (opposite) and (adjacent) are subjective and change depending on the angle one uses in the ratio. However the name (hypotenuse) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.

In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent (tan) ratio.

tan(\theta)=\frac{opposite}{adjacent}

Substitute,

tan(35)=\frac{opposite}{100}

Inverse operations,

tan(35)=\frac{opposite}{100}

100(tan(35))=opposite

Simplify,

100(tan(35))=opposite

70.02\approx opposite

4 0
2 years ago
I need help on these ASAP !!!
liq [111]

Answer:

IDK.

Step-by-step explanation:

Ask ur teacher for help.  

I hope this helps u.

7 0
3 years ago
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Peter and John went shopping and spent ratio 2:3 If Peter spent $500 how much did John spend?
sveta [45]
John spent a total of $750
8 0
3 years ago
What is the decimal form of 17%?
Inessa [10]
17% = 17/100 = 0.17

Answer: 0.17
3 0
3 years ago
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Use the dot product to find |v| when v = (-2,-1)<br> a. -1<br> b. -3<br> C. Root 5<br> D. Root 3
Firdavs [7]
Answer
Root 5 for sure
5 0
3 years ago
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