Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
Answer:
Based on what I can see, the answer is sixteenths.
Step-by-step explanation:
If you count every tick on the line, you can get the number sixteenths. Hope this helped :)
No solution is 3x + 4
One solution is 2x + 4
Infinitely many solution is 3x + 5
Step-by-step explanation:
Answer 8.17
Step-by-step explanation:
1.divide 98 by twelve, since there are 12 inches in a foot
98 \ 12
2.then round to the nearest tenth. 8.16 is rounded to 8.17
Your answer would be -12 because of her answers
