Answer:
A)friction
Explanation:
The friction of air resistance slows down the acceleration due to gravity for real-world objects.
Air resistance is a form of friction found in atmosphere.
Frictional force is a force that opposes the motion of a body. It acts in the opposite direction of motion. Friction slows down real-world objects moving through the air.
Without friction, motion will not be possible.
your answer is the letter (b)
Answer:
10 h
Explanation:
velocidade é a taxa de variação da distância no tempo. é a razão entre a distância e o tempo
de Santos e Curitiba:
distância (d) de 480 km, velocidade (s) de 80 km/h
![s=\frac{d}{t}\\ t=\frac{d}{s} =\frac{480}{80}=6h](https://tex.z-dn.net/?f=s%3D%5Cfrac%7Bd%7D%7Bt%7D%5C%5C%20t%3D%5Cfrac%7Bd%7D%7Bs%7D%20%3D%5Cfrac%7B480%7D%7B80%7D%3D6h)
de Curitiba e Florianópolis:
distância (d) de 300 km, velocidade (s) de 75 km/h
![s=\frac{d}{t}\\ t=\frac{d}{s} =\frac{300}{75}=4h](https://tex.z-dn.net/?f=s%3D%5Cfrac%7Bd%7D%7Bt%7D%5C%5C%20t%3D%5Cfrac%7Bd%7D%7Bs%7D%20%3D%5Cfrac%7B300%7D%7B75%7D%3D4h)
tempo médio de ônibus entre Santos e Florianópolis = 6h + 4h = 10h
2.8km/h see what you do is subtract 12.0 away from 14.8 and that is how you get your answer to the problem.
A)
At time = .003 hr
B)
90* (3*10^-3) = .27km
C)
.005 hr
D)
Car A = 150 * (.005) = .75km
Car B = (90 * (.005) = .45 km
E)
Car A = 150 * (0.008) = 1.2 km
Car B = 90 * (0.008) = 0.72 km
Car A is ahead