Answer:
protected under students first amendment rights
Explanation:
did the studyisland :)
Answer:
![v=d\sqrt{\frac{k}{m}}](https://tex.z-dn.net/?f=v%3Dd%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%7D%20)
Explanation:
In order to solve this problem, we can do an analysis of the energies involved in the system. Basically the addition of the initial potential energy of the spring and the kinetic energy of the mass should be the same as the addition of the final potential energy of the spring and the kinetic energy of the block. So we get the following equation:
![U_{0}+K_{0}=U_{f}+K_{f}](https://tex.z-dn.net/?f=U_%7B0%7D%2BK_%7B0%7D%3DU_%7Bf%7D%2BK_%7Bf%7D)
In this case, since the block is moving from rest, the initial kinetic energy is zero. When the block loses contact with the spring, the final potential energy of the spring will be zero, so the equation simplifies to:
![U_{0}=K_{f}](https://tex.z-dn.net/?f=U_%7B0%7D%3DK_%7Bf%7D)
The initial potential energy of the spring is given by the equation:
![U_{0}=\frac{1}{2}kd^{2}](https://tex.z-dn.net/?f=U_%7B0%7D%3D%5Cfrac%7B1%7D%7B2%7Dkd%5E%7B2%7D)
the Kinetic energy of the block is then given by the equation:
![K_{f}=\frac{1}{2}mv_{f}^{2}](https://tex.z-dn.net/?f=K_%7Bf%7D%3D%5Cfrac%7B1%7D%7B2%7Dmv_%7Bf%7D%5E%7B2%7D%20)
so we can now set them both equal to each other, so we get:
![=\frac{1}{2}kd^{2}=\frac{1}{2}mv_{f}^{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7Dkd%5E%7B2%7D%3D%5Cfrac%7B1%7D%7B2%7Dmv_%7Bf%7D%5E%7B2%7D)
This new equation can be simplified if we multiplied both sides of the equation by a 2, so we get:
![kd^{2}=mv_{f}^{2}](https://tex.z-dn.net/?f=kd%5E%7B2%7D%3Dmv_%7Bf%7D%5E%7B2%7D)
so now we can solve this for the final velocity, so we get:
![v=d\sqrt{\frac{k}{m}}](https://tex.z-dn.net/?f=v%3Dd%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%7D%20)
C Camera. I think this because you can make timelapses with cameras which makes it easy to see.
The minimum value of the coefficient of static friction between the block and the slope is 0.53.
<h3>Minimum coefficient of static friction</h3>
Apply Newton's second law of motion;
F - μFs = 0
μFs = F
where;
- μ is coefficient of static friction
- Fs is frictional force
- F is applied force
μ = F/Fs
μ = F/(mgcosθ)
μ = (250)/(50 x 9.8 x cos15)
μ = 0.53
Thus, the minimum value of the coefficient of static friction between the block and the slope is 0.53.
Learn more about coefficient of friction here: brainly.com/question/20241845
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work done=446.9 J . so option (c) is correct.
Explanation:
the formula for work done is given by
W= F d
F= force= mg where m= mass and g= acceleration due to gravity
F= 3.8 (9.8)=37.24 J
so W=37.24 (12)
W=446.9 J