Answer:
The speed of space station floor is 49.49 m/s.
Explanation:
Given that,
Mass of astronaut = 56 kg
Radius = 250 m
We need to calculate the speed of space station floor
Using centripetal force and newton's second law




Where, v = speed of space station floor
r = radius
g = acceleration due to gravity
Put the value into the formula


Hence, The speed of space station floor is 49.49 m/s.
Answer:
Yes
Explanation:
If the acceleration has an opposite direction to the velocity of the car, this means that it is opposed to is motion. Therefore, it is called deceleration, since the car's velocity will decrease until it stops and then will start it moving towards the west.
Liquid and solid water were not in the giant gas cloudr
Answer:
b. Jupiter’s greater gravity has compressed the layers, so they are closer together there.
Explanation:
The value for Jupiter mass is 1.8981×10²⁷kg, while the mass of Saturn is 5.6832×10²⁶kg, so the different layers of clouds in Jupiter will be submitted to a greater gravitational pull because it has a bigger mass, as is established in the law of universal gravitation:
(1)
Where m1 and m2 are the masses of two objects, G is the gravitational constant and r is the distance between the two objects.
As it can be seen in equation 1, the gravitational force is directly proportional to the product of the masses of the objects, so if the mass increase the gravitational force will do it too.
For the case of Saturn, it has a lower mass so its layers of clouds will suffer a weaker gravitational pull. That leads to the three clouds being more spacing that the ones of Jupiter.
Answer:
<em> The elastic potential energy stored in the bungee cord = 20 J</em>
Explanation:
potential energy: This is the energy possessed by a body due to its position. The S.I unit of energy is Joules. The mathematical expression for elastic potential energy is given below
E = 1/2ke²................ Equation 1
Where E = elastic potential energy of the spring, k = force constant of the spring, e = extension
<em>Given: K = 10 N/m, e = 2.00 m</em>
<em>Substituting these values into Equation 1</em>
<em>E = 1/2(10)(2)²</em>
<em>E = 5×4</em>
<em>E = 20 Joules.</em>
<em>Therefore the elastic potential energy stored in the bungee cord = 20 J</em>
<em></em>