Answer:
t = 0.319 s
Explanation:
With the sudden movement of the athlete a pulse is formed that takes time to move along the rope, the speed of the rope is given by
v = √T/λ
Linear density is
λ = m / L
λ = 4/20
λ = 0.2 kg / m
The tension in the rope is equal to the athlete's weight, suppose it has a mass of m = 80 kg
T = W = mg
T = 80 9.8
T = 784 N
The pulse rate is
v = √(784 / 0.2)
v = 62.6 m / s
The time it takes to reach the hook can be searched with kinematics
v = x / t
t = x / v
t = 20 / 62.6
t = 0.319 s
Find the velocity of the object after one second.
v = vo + at
v = (0 m/s) + (9.8 m/s^2)(1 s)
v = 9.8 m/s
Now, using that, you can find the displacement in that one second between 1 and 2.
d = vot + (1/2)at^2
d = (9.8 m/s)(1 s) + (1/2)(9.8 m/s^2)(1 s)^2
d = 14.7 m
As per Weins displacement law the wavelength of light for which we get the peak of the graph is always inversely proportional to the temperature.
So we can say
So here if temperature becomes more cool then wavelength will increase
here we know that
It means the hottest star out of all three is star 3
and coolest star is star 1
now if we star 2 becomes cooler then it means its temperature will go near to star 1 and hence it will more look like to star 1.
So correct answer is
it will look more like Star 1
The body for which its
(Mass) / (radius squared)
is the greatest.
