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pickupchik [31]
3 years ago
9

tas watches as his uncle changes a flat tire on a car. his uncle raises the car using a machine called a jack. each time his unc

le pushes down on the jack handle, the car rises up. tas sketches the jack and labels it using the symbols f, to represent force, and d, to represent distance. he uses large and small letters to compare the sizes of the forces and distances. which set of labels is correct for the side of the jack that tas’s uncle pushes on? a large f and a small d a small f and a small d a large f and a large d a small f and a large d
Physics
2 answers:
Alenkinab [10]3 years ago
8 0
Small f and large L.

People needs help of machines to increase their force.

People cannot lift a car without a machine.

Using the leverage  or hydraulic principles the machines increase your force.

If you use a large leverage you execute a large movement with little force and as result the ohter side will move small distances with a greater force.

I hope this help. Please, let me know.
kakasveta [241]3 years ago
7 0

The answer is

-Small f and large D.

The explanation:

-when The car jack is an example of a machine, which is defined as anything that a person can use to make the exertion of force easier.

-So with the small force he exerts on the jack, the distance that the car is lifted up increases .

and People needs help of machines to increase their force.  People cannot lift a car without a machine. Using the leverage  or hydraulic principles the machines increase your force.

If you use a large leverage you execute a large movement with little force and as result the other side will move small distances with a greater force.

You might be interested in
A force vector points due east and has a magnitude of 140 newtons. A second force is added to . The resultant of the two vectors
ale4655 [162]

Answer:

(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East

(b)  When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West

Explanation:

Given;

a force vector points due east, F_1 = 140 N

let the second force = F_2

let the resultant of the two vectors = F

(a) When the resultant force is pointing along east line

the second force must be pointing due east

F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N

F_2 = 280 \ East

(b) When the resultant force is pointing along west line

the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.

F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N

F_2 = 560 \ West

8 0
3 years ago
Assume that a pendulum used to drive a grandfather clock has a length L0=1.00m and a mass M at temperature T=20.00°C. It can be
Sedaia [141]

Answer:

The period will change a 0,036 % relative to its initial state

Explanation:

When the rod expands by heat its moment of inertia increases, but since there was no applied rotational force to the pendulum , the angular momentum remains constant. In other words:

ζ= Δ(Iω)/Δt, where ζ is the applied torque, I is moment of inertia, ω is angular velocity and t is time.

since there was no torque ( no rotational force applied)

ζ=0 → Δ(Iω)=0 → I₂ω₂ -I₁ω₁ = 0 → I₁ω₁ = I₂ω₂

thus

I₂/I₁ =ω₁/ω₂ , (2) represents final state and (1) initial state

we know also that ω=2π/T , where T is the period of the pendulum

I₂/I₁ =ω₁/ω₂ = (2π/T₁)/(2π/T₂)= T₂/T₁

Therefore to calculate the change in the period we have to calculate the moments of inertia. Looking at tables, can be found that the moment of inertia of a rod that rotates around an end is

I = 1/3 ML²

Therefore since the mass M is the same before and after the expansion

I₁ = 1/3 ML₁² , I₂ = 1/3 ML₂²  → I₂/I₁ = (1/3 ML₂²)/(1/3 ML₁²)= L₂²/L₁²= (L₂/L₁)²

since

L₂= L₁ (1+αΔT) , L₂/L₁=1+αΔT  , where ΔT is the change in temperature

now putting all together

T₂/T₁=I₂/I₁=(L₂/L₁)² = (1+αΔT) ²

finally

%change in period =(T₂-T₁)/T₁ = T₂/T₁ - 1 = (1+αΔT) ² -1

%change in period =(1+αΔT) ² -1 =[ 1+18×10⁻⁶ °C⁻¹ *10 °C]² -1 = 3,6 ×10⁻⁴ = 3,6 ×10⁻² %  = 0,036 %

4 0
3 years ago
Enumerate the viscosity of magma in different conditions.
Firlakuza [10]

Answer:

The nature of volcanic eruptions is highly dependent on magma viscosity and also on dissolved gas content. ... long it takes the treacle to flow from one end of a boiling tube to the other.

3 0
3 years ago
Make a general statement about what happens to light as it enters a different medium.
Aleksandr-060686 [28]

Answer:

Refraction is an effect that occurs when a light wave, incident at an angle away from the normal, passes a boundary from one medium into another in which there is a change in velocity of the light. The wavelength decreases as the light enters the medium and the light wave changes direction.

Explanation:

4 0
3 years ago
A hotel wants to put a fence around a circular spa. The radius of the spa is 5/√2-1 feet. If the fence is built along the immedi
Vlad [161]
It is important to look at all the information's that are given in the question very closely. Let us write them write first.

Radius of the spa = <span>5/√2-1 feet
Now
Perimeter of the circle = </span><span>2πr
                                    = 2</span>π (5/√2-1) 
                                    = <span>π(5/(√2-1)*(√2+1)/(√2+1) </span>
<span>                                    = 2π(5/(√2+1))/(2-1) </span>
<span>                                    = 10π(√2+1)  

I hope that the procedure is clear enough for you to understand.</span>
5 0
3 years ago
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