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pickupchik [31]
3 years ago
9

tas watches as his uncle changes a flat tire on a car. his uncle raises the car using a machine called a jack. each time his unc

le pushes down on the jack handle, the car rises up. tas sketches the jack and labels it using the symbols f, to represent force, and d, to represent distance. he uses large and small letters to compare the sizes of the forces and distances. which set of labels is correct for the side of the jack that tas’s uncle pushes on? a large f and a small d a small f and a small d a large f and a large d a small f and a large d
Physics
2 answers:
Alenkinab [10]3 years ago
8 0
Small f and large L.

People needs help of machines to increase their force.

People cannot lift a car without a machine.

Using the leverage  or hydraulic principles the machines increase your force.

If you use a large leverage you execute a large movement with little force and as result the ohter side will move small distances with a greater force.

I hope this help. Please, let me know.
kakasveta [241]3 years ago
7 0

The answer is

-Small f and large D.

The explanation:

-when The car jack is an example of a machine, which is defined as anything that a person can use to make the exertion of force easier.

-So with the small force he exerts on the jack, the distance that the car is lifted up increases .

and People needs help of machines to increase their force.  People cannot lift a car without a machine. Using the leverage  or hydraulic principles the machines increase your force.

If you use a large leverage you execute a large movement with little force and as result the other side will move small distances with a greater force.

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RoseWind [281]

Answer:

(a): a = 0.4m/s²

(b): α = 8 radians/s²

Explanation:

First we propose an equation to determine the linear acceleration and an equation to determine the space traveled in the ramp (5m):

a= (Vf-Vi)/t = (2m/s)/t

a: linear acceleration.

Vf: speed at the end of the ramp.

Vi: speed at the beginning of the ramp (zero).

d= (1/2)×a×t² = 5m

d: distance of the ramp (5m).

We replace the first equation in the second to determine the travel time on the ramp:

d = 5m = (1/2)×( (2m/s)/t)×t² = (1m/s)×t ⇒ t = 5s

And the linear acceleration will be:

a = (2m/s)/5s = 0.4m/s²

Now we determine the perimeter of the cylinder to know the linear distance traveled on the ramp in a revolution:

perimeter = π×diameter = π×0.1m = 0.3142m

To determine the angular acceleration we divide the linear acceleration by the radius of the cylinder:

α = (0.4m/s²)/(0.05m) = 8 radians/s²

α: angular aceleration.

3 0
3 years ago
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Answer: 8 meters per second

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Gina is driving her car down the street. She has a teddy bear sitting on the back seat. A dog runs in front of Gina's car, so sh
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<span>A.frictional effects dissipate energy.</span>
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A 17926-lb truck enters an emergency exit ramp at a speed of 75.6 ft/s. It travels for 6.4 s before its speed is reduced to 30.3
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Answer:

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