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Rom4ik [11]
4 years ago
15

5. You're examining some of the tiny printing on one of the newer twenty-dollar bills. A 1.5 mm tall letter appears 3 mm tall an

d upright when viewed through a converging lens. If the lens is held 4 cm from the bill, what is the focal length of the lens
Physics
2 answers:
kow [346]4 years ago
5 0

Answer:

80mm or 8cm

Explanation:

According to the lens formula,

1/f = 1/u+1/v

If the object distance u = 4cm = 40mm

Object height = 1.5mm

Image height = 3mm

First, we need to get the image distance (v) using the magnification formula Magnification = image distance/object distance = Image height/object height

v/40=3/1.5

1.5v = 120

v = 120/1.5

v = 80mm

The image distance is 80mm

To get the focal length, we will substitute the image distance and the object distance in the mirror formula to have;

1/f = 1/40+1/-80

Note that the image formed by the lens is an upright image (virtual), therefore the image distance will be negative.

Also the focal length of the converging lens is positive. Our formula will become;

1/f = 1/40-1/80

1/f = 2-1/80

1/f = 1/80

f = 80mm

The focal length of the lens 80mm or 8cm

Paraphin [41]4 years ago
4 0

Answer: f = 4cm

Explanation: The lateral magnification formulae is given as

m = height of image /height of object or

m = - (image distance) /(object distance)

Image height (Hi) = 3mm, object height (Hob) = 1.5mm, object distance (u) =?, image distance (v) = - 4cm... The reason we have a negative image distance is because the image is upright and an upright image (aka virtual image) has negative image distance because the the refracting ray is on the opposite side of the image.

m = Hi/Hob

m = 3/1.5 = 2.

Since m =2, and v = - 4cm, we can get 'u' as follows

m = - v/u

2 = - (-4)/u

2 = 4/u

2u = 4, u = 4/2, u = 2cm.

Using the lens formulae

1/u + 1/v = 1/f

1/2 - 1/4 = 1/f

0.5 - 0.25 = 1/f

0.25 = 1/f

f = 1/ 0.25

f = 4cm

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Answer:

Explanation:

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Use first equation of motion for rotational motion

ω = ωo + αt

ω = 0 + 30.5 x 9

ω = 274.5 rad/s

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v = 32.94 m/s

8 0
3 years ago
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Arte-miy333 [17]

Answer:

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Explanation:

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pychu [463]

Answer:

They have different wavelengths.

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Explanation:

The complete question is

Consider the following:

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They have different wavelengths.

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They require different media to propagate.

All the above phenomena are due the electromagnetic wave spectrum. Electromagnetic waves travel at a constant speed of 3 x 10^8 m/s in a vacuum. Within the spectrum, the different types of electromagnetic waves exists in different band range of frequencies and wavelengths unique to each of the waves, and the energy they carry. When these waves enter a non-vacuum medium, their speed change, depending on the nature of the material of the medium, and the frequency or the wavelength of the incoming wave.

5 0
4 years ago
Two balls have their centers 2.0 m apart. One ball has a mass of m1 = 7.9 kg. The other has a mass of m2 = 6.1 kg. What is the g
maks197457 [2]

Answer:

3.036×10⁻¹⁰ N

Explanation:

From newton's law of universal gravitation,

F = Gm1m2/r² .............................. Equation 1

Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.

G = gravitational constant

Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²

Substituting into equation 1

F = 6.67×10⁻¹¹×7.9×6.1/2²

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Maurinko [17]
18/40=.45
so, .45 of a second
4 0
4 years ago
Read 2 more answers
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