All categories

3 years ago

derive formula of kinetic energy of particular having mass volume and velocity of dimensional analysis

Physics

1 answer:

natita [175]3 years ago

4 0

Answer:

E=1/2kmv^2

Explanation:

To get the formula...

The dimension of energy is [ M^1 L^2 T^-2]

The dimension of mass [M]=[M^1 L ^0T ^0]

Dimension of velocity[V]=[M ^0 L ^1 T ^−1]

Let [E]=k[M] ^x[V] ^y

K is constant and it remain a dimensionless quantity.

Therefore, M ^1L ^2T ^−2]=k[M ^1L ^0T ^0] x[M ^0L ^1 T ^−1] y

So, x=1,y=2

E= Kmv^2

K=1/2

Therefore E is 1/2kmv^2.

You might be interested in

Suppose that Lisa walks her dog around the block for a little exercise. The block is 1 mile around. If she walks around the bloc

natita [175]

Displacement only measure how far between the starting and ending point. In this case, Lisa walks around the block as a circle so the starting point is the same as the ending point. Thus, displacement is 0mile.
On the other hand, distance measures exactly how far she walks. In this case, the distance is 1 mile, same as the perimeter of the block.

7 0

3 years ago

What is earths magnetism

vivado [14]

Answer:

Magmatism is the emplacement of magma within and at the surface of the outer layers of a terrestrial planet, which solidifies as igneous rocks. ... On Earth, magma forms by partial melting of silicate rocks either in the mantle, continental or oceanic crust.

Explanation:

4 0

3 years ago

Read 2 more answers

What are things measured by mass

Free_Kalibri [48]

Anything that is possibly solid or can be contained in a solid

Mass is the amount of matter that is contained in a certain object.
Like
20 kg
10 g
100 lb

6 0

3 years ago

Two particles are fixed to an x axis: particle 1 of charge q1 = 2.78 × 10-8 c at x = 15.0 cm and particle 2 of charge q2 = -3.24

Oksi-84 [34.3K]

Refer to the attached figure. Xp may not be between the particles but the reasoning is the same nonetheless.
At xp the electric field is the sum of both electric fields, remember that at a coordinate x for a particle placed at x' we have the electric field of a point charge (all of this on the x-axis of course):
$E=\frac{1}{4\pi\varepsilon_0}\frac{q}{(x-x')^2}$
Now At xp we have:
$\frac{1}{4\pi\varepsilon_0}\frac{q_1}{(x_p-x_1)^2}-\frac{1}{4\pi\varepsilon_0}\frac{3.29q_1}{(x_p-x_2)^2}=0$
$\implies (x_p-x_1)^2=\frac{(x_p-x_2)^2}{3.29}\\
\implies(1-\frac{1}{3.29})x_p^2+2(\frac{x_2}{3.29}-x_1)x_p+x_1^2-\frac{x_2^2}{3.29}=0$
Which is a second order equation, using the quadratic formula to solve for xp would give us:
$xp=\frac{-(\frac{x_2}{3.29}-x_1)-\sqrt{(\frac{x_2}{3.29}-x_1)^2-(1-\frac{1}{3.29})(x_1^2-\frac{x_2^2}{3.29})}}{(1-\frac{1}{3.29})}$
or
$xp=\frac{-(\frac{x_2}{3.29}-x_1)+\sqrt{(\frac{x_2}{3.29}-x_1)^2-(1-\frac{1}{3.29})(x_1^2-\frac{x_2^2}{3.29})}}{(1-\frac{1}{3.29})}$
Plug the relevant values to get both answers.
Now, let's comment on which of those answers is the right answer. It happens that BOTH are correct. This is simply explained by considring the following.

Let's place a possitive test charge on the system This charge feels a repulsive force due to q1 but an attractive force due to q2, if we place the charge somewhere to the left of q2 the attractive force of q2 will cancel the repulsive force of q1, this translates to a zero electric field at this x coordinate. The same could happen if we place the test charge at some point to the right of q1, hence we can have two possible locations in which the electric field is zero. The second image shows two possible locations for xp.

6 0

4 years ago

How many molecules are in 3 moles of CO2

mote1985 [20]

Answer:

There are 1.806 X 1024 molecules in 3 moles of CO2. This concept is similar to counting 144 eggs and dividing by 12 to get the number of cartons.

8 0

3 years ago

Read 2 more answers

derive formula of kinetic energy of particular having mass volume and velocity of dimensional analysis​

derive formula of kinetic energy of particular having mass volume and velocity of dimensional analysis