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Ne4ueva [31]
2 years ago
7

A rotating water pump works by taking water in at one side of a rotating wheel, and expelling it from the other side. If a pump

with a radius of 0.120 m starts from rest and accelerates at 30.5 rad/s2, how fast will the water be traveling when it leaves the pump after it has been accelerating for 9.00 seconds
Physics
1 answer:
Xelga [282]2 years ago
8 0

Answer:

Explanation:

initial angular velocity, ωo = 0 rad/s

angular acceleration, α = 30.5 rad/s²

time, t = 9 s

radius, r = 0.120 m

let the velocity is v after time 9 s.

Use first equation of motion for rotational motion

ω = ωo + αt

ω = 0 + 30.5 x 9

ω = 274.5 rad/s

v = rω

v = 0.120 x 274.5

v = 32.94 m/s

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The specific heat of substance A is greater than that of substance B. Both A and B are at the same initial temperature when equa
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Explanation:

For this case we know the following info:

c_{pA} > c_{pB}

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We also know that the initial temperatures for both sustances are equal:

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We assume that we don't have melting or vaporization in the 2 substances. So we just have presence of sensible heat given by this formula:

Q = m c_p \Delta T

And for this case we know that Both A and B are at the same initial temperature when equal amounts of energy are added to them, so then we have this:

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And if we replace the formula for sensible heat we got:

m_A c_{pA} \Delta T_A = m_B c_{pB} \Delta T_B

And if we replace for the change of the temperature we got:

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And since T_{iA}= T_{iB}= T we have this:

m_A c_{pA} (T_{fA} -T) = m_B c_{pB} (T_{fB}- T)

For this case, if we try to find the final temperature of A and B, we see that we will obtain an expression in terms of specific heats and masses, from the information given we know the relationship between specific heats, but we don't know the relationship that exists among the masses, then the best option for this case is:

d) More information is needed

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anyanavicka [17]

Answer:

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Explanation:

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