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Doss [256]
2 years ago
10

What conclusions can you make if a hockey goalie fails to block pucks shot in the upper right hand corner of the net

Physics
1 answer:
Lemur [1.5K]2 years ago
3 0

Given what we know, we can confirm that this result from the goalie is a clear indicator of room for improvement in the reaction speed and visual coordination for this area of the net.

<h3>How can the goalie improve reaction speeds to this area?</h3>

The key for situations like this is simply repetition. The more the goalie is able to practice with shots in this area of the net, the more muscle memory they will build regarding reacting to these shots, and therefore less time will be needed to block them in the future.

Therefore, we can confirm that this result from the goalie is a clear indicator of room for improvement in the reaction speed and visual coordination for this area of the net.

To learn more about reaction speeds visit:
brainly.com/question/8186329?referrer=searchResults

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Sunday, July 20, marked 45 years since the United States put the first two astronauts safely on the moon. The cost for the Mercury, Gemini and Apollo programs was more than $25 billion at the time more like $110 billion in today’s world. The ensuing U.S. space efforts have cost an additional $196 billion for the shuttle and $50 billion for the space station. NASA’s total inflation-adjusted costs have been more than $900 billion since its creation in 1958 through 2014 (more than $16 billion per year). Looking back, have we gotten our money’s worth from the investment?

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Technician A says that the evacuation process will remove dirt and debris from the refrigerant system. Technician B says that th
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After an incandescent lamp is turned on, the temperature of its filament rapidly increases from room temperature to its operatin
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A uniformly charged conducting sphere of 1.1 m diameter has a surface charge density of 6.2 µC/m2. (a) Find the net charge on th
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Answer:

(a) q = 2.357 x 10⁻⁵ C

(b) Φ = 2.66 x 10⁶ N.m²/C

Explanation:

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radius of the sphere, r = 1.1 / 2 = 0.55 m

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4πr² is surface area of the sphere

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