Question

At a certain location, Earth has a magnetic field of 0.60 ✕ 10−4 T, pointing 75° below the horizontal in a north-south plane. A 15.0 m long straight wire carries a 19 A current. (a) If the current is directed horizontally toward the east, what are the magnitude and direction of the magnetic force on the wire? magnitude N

Answer 1

Answer with Explanation:

We are given that

Magnetic field,B=$0.6\times 10^{-4} T$

$\theta=75^{\circ}$

Length of wire,l=15 m

Current,I=19 A

a.We have to find the magnitude of magnetic force and direction of magnetic force.

Magnetic force,F=$IBlsin\theta$

Using the formula

$F=0.6\times 10^{-4}\times 15\times 19sin75$

$F=16.5\times 10^{-3} N$

Direction=$tan\theta=cot(90-75)=tan15^{\circ}$

$\theta=15^{\circ}$

15 degree above the horizontal  in the northward direction.