Answer:
4.6 is 5 , 0.5 is 1, 4.5 is 5, 5.5 is 6 and 0.6 is 1
Step-by-step explanation:
If the second digit after the decimal is 5 or high you round it up
Answer:
x = 2
Step-by-step explanation:
(16 =
and 8 =
)

Since the base number is 2, the exponents must equal each other.
So:
12x = 3x+18
9x = 18
x = 2
Answer:
Less
Step-by-step explanation:
Let the measure of side AB be x, then, the measue of side AE is given by

.
Now, ABCD is a square of size x, thus the area of square ABCD is given by

Also, AEFG is a square of size

, thus, the area of square AEFG is given by

<span>The sum of the areas of the two squares ABCD and AEFG is given by

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>
First one is y=4x and the second one is y=2x