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Nata [24]
3 years ago
8

Tell if is: < or > ​

Mathematics
1 answer:
Eva8 [605]3 years ago
7 0

Answer:

-2>-5

4/7<3/5

-1.3>-1.333333

Step-by-step explanation:

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Solve each triangle. Round your answers to the nearest tenth
ivolga24 [154]
You have to use the Law of Cosines here, since there's no other way to solve this.  it's not a right triangle, so you can't use the Pythagorean Theorem.  The Law of Cosines will help us find the missing side length then we will have to use the Law of Sines to find another angle.  Then after that we will use the Triangle Angle-Sum theorem to finish it off.  Ready? The Law of Cosines to find side b isb^{2} = a^{2}+ c^{2} -2ac cosB and fill in the info we know, which is everything but the b. b^{2} =(21) ^{2} +(29) ^{2} -2(21)(29)cos109. Doing all that math gives us that side b = 40.9 or 41. Now the Law of Sines to find missing angle A or C.  Let's find A. \frac{sinA}{21} = \frac{sin109}{41}.  That gives us that angle A is 29.  Now use the fact that all triangles add up to 180 to get that angle C is 42.  And you're done!

7 0
3 years ago
A line passes through the points (1, 2) and (3, 1). What is the slope of the line?
erastovalidia [21]
M = 1 - 2 / 3 - 1
m = - 1 / 2
8 0
3 years ago
Which equation represents a parabola that opens upward, has a minimum value of 3, and has an axis of symmetry at x= 3?
Ilya [14]

Answer:

y=(x-3)^2+3

Step-by-step explanation:

<u><em>The correct question is</em></u>

Which equation represents a parabola that opens upward, has a minimum value of y=3, and has an axis of symmetry at x= 3?

<em>Verify each case</em>

case 1) we have

y=(x+3)^2-6

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (-3,-6)

The minimum value of y=-6 ----> is not ok

The axis of symmetry is x=-3 ----> is not ok

case 2) we have

y=(x+3)^2+3

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (-3,3)

The minimum value of y=3 ----> is ok

The axis of symmetry is x=-3 ----> is not ok

case 3) we have

y=(x-3)^2-6

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (3,-6)

The minimum value of y=-6 ----> is not ok

The axis of symmetry is x=3 ----> is ok

case 4) we have

y=(x-3)^2+3

This a vertical parabola open upward (the leading coefficient is positive)---> is ok

The vertex represent a minimum ---> is ok

The vertex is the point (3,3)

The minimum value of y=3 ----> is ok

The axis of symmetry is x=3 ----> is ok

6 0
3 years ago
Find each angle measure to the nearest degree
IRISSAK [1]

Answer:

RS=26.49 m;

ST =14.08 m;

m<R =28°

Step-by-step explanation:

7 0
2 years ago
While visiting Wallawulla State​ Park, Joe approximated the angle of elevation to the top of a mound to be 40 degrees . After wa
katen-ka-za [31]

Answer:

Height of mound = 794 ft

Step-by-step explanation:

To illustrate the angle of elevation and distance, i have drawn it and attached below.

Now, from my diagram;

h = the height of the mound

At his first point of his trip to the foot of the mound, the angle of elevation is 40°, while the horizontal distance to the foot of the mound is "X"

So, by triangle definition,

tan(40°) = h/x

And so;

h = x tan40

h = 0.8391x  - - - - (eq 1)

At his second point of the trip to the foot of the mound, Joe is now,

"(x - 450) ft" from the foot of the mound.

Thus, his angle of elevation is 40 + 18 = 58°.

So, by triangle definition,

tan(58°) = h/(x - 450)

h = (x - 450)•(tan(58°))

h = 1.6003(x - 450)

h = 1.6003x - 720.135   - - - - -(eq2)

To get the height(h) of the mound, let's equate (eq1) to (eq2).

0.8391x = 1.6003x - 720.135

1.6003x - 0.8391x = 720.135

0.7612x = 720.135

x = 720.135/0.7612

x = 946.0523 ft

Let's put this value for x in eq (1);

h = 0.8391 x 946.0523 = 793.83 ft ≈ 794ft

4 0
3 years ago
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