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Sophie [7]
3 years ago
9

Sections of prefabricated fencing are each 4 1/3 feet long. how long are 6 1/2 sections placed end to end

Mathematics
2 answers:
zalisa [80]3 years ago
6 0

we know that

4\frac{1}{3}= \frac{(4*3+1)}{3} =\frac{13}{3}

6\frac{1}{2}= \frac{(6*2+1)}{2}=\frac{13}{2}

To find how long are 6\frac{1}{2}  sections placed end to end

Multiply the number of sections by the length of one section

so

\frac{13}{2} *\frac{13}{3} =\frac{169}{6}\ ft

\frac{169}{6}\ ft =28\frac{1}{6}\ ft

therefore

<u>the answer is</u>

28\frac{1}{6} \ ft


ladessa [460]3 years ago
6 0
Each section is 4 1/3 feet long.
6 1/2 section will be 4 1/3 x 6 1/2 = 13/3 x 13/2 = 169/6 = 28 1/6 feet

Thus, 6 1/2 sections will be 28 1/6 feet long.
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Answer:

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the answer is, 1 - bin(k=0, n=4, r=1/6) - bin(k=1, n=4, r=1/6). This evaluates to about 13%, just like your result (you just computed all three outcomes satisfying the proposition rather than the two that didn’t).

Step-by-step explanation:

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2 years ago
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Answer:

Area =55.4ft^2

Step-by-step explanation:

Given

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Required

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\tan(60) = \frac{4\sqrt 3}{x}

Solve for x

x = \frac{4\sqrt 3}{\tan(60)}

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3 years ago
8(7n-2) -6(7n+1)<br><br> Explain please
Verizon [17]

Answer:

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Step-by-step explanation:

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8 0
1 year ago
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vitfil [10]

Step-by-step explanation:

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