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natta225 [31]
3 years ago
15

The daytime temperature in Apple Valley is falling by 2.5 degrees each day. What will the net change in the daily temperature be

after one calendar week?
Mathematics
2 answers:
lisabon 2012 [21]3 years ago
8 0
17.5 i think, i mean dont hold it against me if not but i multiplied 2.5 and 7 sooo
stealth61 [152]3 years ago
8 0

Answer:

17.5

Step-by-step explanation:

You might be interested in
Triangle ABCis rotated 90° clockwise around the origin to get
Elanso [62]

Answer:

The distance A’C’ is 4.47 units

Step-by-step explanation:

Before we go on, we need to get the appropriate transformation

Mathematically, we have a 90 degrees clockwise rotation yielding the following;

(x,y) to (-y,x)

A is (-4,1)

C is (-2,5)

By transforming, we have

A’( -1,-4)

C’ (-5,-2)

To get the magnitude of the line segment, we are going to use the distance formula between points

We have this as;

D = √(x2-x1)^2 + (y2-y1)^2

D = √(-5-(-1))^2 + (-2-(-4))^2

D = √(-4)^2 + (2)^2

D = √(16 + 4)

D = √20

D = 4.47 units

7 0
2 years ago
-4r-8(r-6)=7(5r-1)+8
KATRIN_1 [288]

Answer:

r = 1

Step-by-step explanation:

In this question, we have to solve for the vallue of "r". We will use the distributive property shown below to ease our process.

Distributive Property:

a(b+c) = ab + ac

Now, lets solve this:

-4r-8(r-6)=7(5r-1)+8\\-4r-8r+48=35r-7+8\\-12r+48=35r+1\\48-1=35r+12r\\47=47r\\r=\frac{47}{47}\\r=1

As we have seen the value of r is "1"

6 0
3 years ago
Suppose the horses in a large stable have a mean weight of 1467lbs, and a standard deviation of 93lbs. What is the probability t
krok68 [10]

Answer:

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 1467, \sigma = 93, n = 49, s = \frac{93}{\sqrt{49}} = 13.2857

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable?

This is the pvalue of Z when X = 1467 + 9 = 1476 subtracted by the pvalue of Z when X = 1467 - 9 = 1458.

X = 1476

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1476 - 1467}{13.2857}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 1458

Z = \frac{X - \mu}{s}

Z = \frac{1458 - 1467}{13.2857}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

5 0
3 years ago
The image of a point after a –90° rotation about the origin is (–4, 7). What are the coordinates of the preimage?.
ahrayia [7]
The coordinated of the preimage would be :

x  = x cos θ + y sin θ

y = x sin θ + y cos θ

where 

x = -4  
y = 7
θ = -90

hope this helps
4 0
3 years ago
PLZ NEED AN ANSWER FAST WORTH 5 TO 10 POINTS
worty [1.4K]

n - 12 = -9

Add 12 to both sides to isolate the variable n.

n = -9 + 12

n = 3

B) n = 3

4 0
3 years ago
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