The likelihood that the first two offspring of the cross will have congenital analgesia would be 1/16
<h2>Autosomal Recessive Traits</h2>
For autosomal recessive traits, two recessive alleles are needed for the trait to manifest while one recessive allele means heterozygosity.
In this case, let us assume that congenital analgesia is represented by the allele b; heterozygous individuals will, thus, be Bb.
Bb x Bb
BB Bb Bb bb
Probability of producing unaffected offspring = 3/4
Probability of producing affected offspring = 1/4
Likelihood of the first two offspring having congenital analgesia = probability of first having congenital analgesia and the second having congenital analgesia
= 1/4 x 1/4
= 1/16
More on genetical probabilities can be found here: brainly.com/question/851793?referrer=searchResults
Biological dyes work by adhering to various biological parts. Different dyes adhere to the different constituents of the cellular membranes, other attach to the proteins, carbohydrates, or lipids.
Some dyes are specific to the cell, and attach to the constituents of those specific cells only.
Answer: A pictograph is a symbol for a word or phrase.
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Answer:
The "short tail" dominant allele is easier to eliminate by selective breeding.
Explanation:
The only way for a recessive allele to be expressed (be visible) is when it appears as recessive homozygotic. These means the organisms need to have 2 copies of the gene. Selective breeding is based on the characteristics that one can see, so if the organism shows the "dilute" phenotype you can keep reproducing this individuals and get rid of the dominant allele.
On the other hand if you have a population with the dominant phenotype, you discard all the ones that have a recessive trait and you breed the dominant phenotype you could still get individuals with the recessive phenotype and individuals that express the dominant phenotype but are heterozygous.
