Hi! I am not quite sure about the answer, but maybe try an equation I learned: y=kx and y/x = x? Maybe try and subtract the fractions or cross equalize? I am happy to give ideas!
Total outcome is 50 [because the number produced by the machine is from 1 to 50]
Question a:
Multiple of 10 are 10, 20, 30, 40, 50
There are five possible outcomes for multiple of 10
P(Multiple of 10) = 5/50 = 1/10
Question b:
Number 1 to 50 will be all the outcomes that are not 100
There are 50 possible outcomes
P(not 100) = 50/50 = 1
Question c:
Multiple of 4 that are less than 50 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48
There are 12 possible outcomes for multiple of 4
We want 'not multiple of 4' so we need to do 50 - 12 = 38 outcomes
P(not a multiple of 4) = 38/50 = 19/25
Question d:
One digit numbers are 1, 2, 3, 4, 5, 6, 7, 8, 9
There are 9 possible outcomes
P(one-digit number) = 9/50
Assuming y represents the grade earned and x represents hours studied, the fact that y=65.8 when x=0 means ...
A) If they studied 0 hours they would earn a 65.8.
<h3>
Answer: 8(x^2-3)</h3>
Since 24 = 8*3, we can factor out the GCF 8 like so
8x^2 - 24 = 8*x^2 - 8*3 = 8(x^2-3)
This is using the distributive property.
